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3 years ago

Solve for x. (1/3) over 3 =x over 8

Mathematics

2 answers:

Ugo [173]3 years ago

8 0

8/3=3x (cross multiplied to get this)

X=8/9 (divided both sides by 3)

Hope this helps :)

gtnhenbr [62]3 years ago

3 0

$\dfrac{\dfrac{1}{3}}{3}=\dfrac{x}{8}\\\\ \dfrac{1}{9}=\dfrac{x}{8}\\\\ 9x=8\\\\ x=\dfrac{8}{9}\\$

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Mr.rivas bought a can of paint.he used 3/8 of it to paint a bookshelf.he used 1/4 of it to paint a wagon.he used some of it to p

9966 [12]

The answer is 1/4

because you can add the 3/8 and 1/4, which it will be 5/8.
Then add 5/8 and 1/8 then it eqaul to 6/8
then subtract 1 by 6/8
then you got 2/8 or 1/4

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3 years ago

The number of earthquake tremors in a 12-month period appears to be distributed as a Poisson random variable with a mean of 6. A

vova2212 [387]

Answer:

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Download docx

3 0

3 years ago

Can I please have help with question 2) a and b

Ulleksa [173]

Answer:

$\frac{10\sqrt{6} }{3}$ and $\frac{11\sqrt{3} }{3}$

Step-by-step explanation:

(a)

A = $\frac{1}{2}$ × 4 $\sqrt{2}$ × $\frac{5}{\sqrt{3} }$

= 2 $\sqrt{2}$ × $\frac{5}{\sqrt{3} }$

= $\frac{10\sqrt{2} }{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ ← rationalise the denominator

= $\frac{10\sqrt{6} }{3}$ units²

(b)

Using Pythagoras' identity in the right triangle

let hypotenuse be h , then

h² = (4 $\sqrt{2}$ )² + ( $\frac{5}{\sqrt{3} }$ )²

= 32 + $\frac{25}{3}$

= $\frac{96}{3}$ + $\frac{25}{3}$

= $\frac{121}{3}$ ( take the square root of both sides )

h = $\sqrt{\frac{121}{3} }$ = $\frac{11}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ ← rationalise the denominator

h = $\frac{11\sqrt{3} }{3}$

7 0

3 years ago

Elijah played in a golf tournament. For the first three days he averaged a score of -2. On the fourth day he shot a +2. What was

pogonyaev

-2, -2, -2, +2

-2 + -2 + -2 + 2
-2 -2 -2 + 2
-6 + 2
-4
-4/ 4 = -1

His average is -1

4 0

4 years ago

Read 2 more answers

The following data set represents the age of

Julli [10]

$\huge\text{Hey there!}$

$\huge\textsf{Breaking the meaning down in simpler terms}$
$\huge\textbf{Median:}\\\large\text{is understood to be \bf the number in the center (also known as}\\\large\textbf{the middle number)}$

$\huge\textbf{Mean:}\\\large\text{is understood to be the \bf total.}$

$\huge\textsf{Formulas for each term}$

$\huge\text{Median:}\\\large\textsf{To find the median you have to put each of your numbers in your data}\\\large\textsf{set from LEAST (smallest) to GREATEST (biggest). }$

$\huge\text{Mean:}\\\mathsf{\dfrac{sum\ of\ all\ terms}{number\ of\ terms}= mean}$

$\huge\textbf{SOLVING FOR THE QUESTION}$

$\huge\textsf{Median:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textbf{Conversion: }\large\text{27, 33, 38, 41, 42, 52, 64, 68, 72}\\\\\large\textsf{Make sure it is even between both sides of the data plot.}\\\\\large\text{It seems to even on BOTH sides of \boxed{\textsf{14}} so it could possibly be your}\\\large\text{median.}$

$\huge\textsf{Mean:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textsf{Your equation: }\mathsf{\dfrac{27 + 52 + 64 + 41 + 33 + 38 + 42 + 60 +72 + 68}{10}}\\\\\mathsf{\dfrac{79 + 64 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{143 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{184 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{217 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{255 + 42 + 60 + 72 + 68}{10}}$

$\mathsf{\dfrac{297 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{357 + 72 + 68}{10}}\\\\\mathsf{\dfrac{429 + 68}{10}}\\\\\mathsf{\dfrac{497}{10}}\\\\\mathsf{\approx 49.70}\\\\\large\text{From the looks of it \boxed{\rm{\dfrac{497}{10}}}\ or \boxed{\text{49.70}} could possibly be your mean.}$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

<h3>
~ $\frak{Amphitrite1040:)}$ </h3>

8 0

3 years ago