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BlackZzzverrR [31]

3 years ago

15

Let f,g,Andy be functions such that f(x) A) f(2)=h(2)=g(2)=4 B) h(x) C) h(x) D) f(x), g(x), and h(x) are all continuous on t

he open interval (-1,3)

1 answer:

Viefleur [7K]3 years ago

3 0

Answer:

is there a graph

Step-by-step explanation:

.

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the area of a square floor on a scale drawing is 100 square centimeters, and the scale of the drawing is 1 cm: 2 ft. what is the

kondaur [170]

The square root of 100 is 10. The drawing must be 10 cm by 10 cm.

1 cm = 2 ft, so 10 cm must equal 20 feet.

20 * 20 = 400 square feet :)

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3 years ago

katie collected 470 cans the first week of the school project. The second week she collected 105 less than the first week. How m

valentinak56 [21]

Answer:

Katie collected 365 cans in the second week.

Step-by-step explanation:

Because Katie collected 470 cans in the first week, and 105 less in the second week, we know to subtract 105 from 470, which gives us 365 cans.

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3 years ago

Three times the square of a certain positive number exceeds six times the number by nine. find the number:

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With the number being x, we have 3x^2>6(x/9). Expanding, we get 3x^2>6x/9 and 3x^2>2x/3. Dividing by x, we get 3x>2/3 and dividing by 3 we get x>2/9

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3 years ago

Y - 11 = 3(x-2) write an equation in slope intercept form

Alekssandra [29.7K]

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7 0

4 years ago

What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table?

sveta [45]

Answer: A B

Group 1 0.25 0.75

Group 2 0.44 0.56

Step-by-step explanation:

Since we have given that

Number of people of A in group 1 = 15

Number of people of B in group 1 = 45

Total number of people in group 1 is given by

$15+45=60$

Relative frequency of people of A in Group 1 is given by

$\frac{15}{60}=0.25$

Relative frequency of people of B in Group 1 is given by

$\frac{45}{60}=0.75$

Similarly, Number of people of A in group 2 = 20

Number of people of B in group 2 = 25

Total number of people in group 2 is given by

$20+25=45$

Relative frequency of people of A in Group 2 is given by

$\frac{20}{45}=0.44$

Relative frequency of people of B in Group 2 is given by

$\frac{25}{45}=0.56$

Hence, A B

Group 1 0.25 0.75

Group 2 0.44 0.56

6 0

3 years ago