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3 years ago

10

Which subject occurs most often in the world’s art?

2 answers:

Sedaia [141]3 years ago

8 0

Looking into previous and current arts that are most famous in the world, we can determine that one of the most often subject is woman. This is simply because they are pleasing to look at. Several other subjects were also used in arts.

SIZIF [17.4K]3 years ago

5 0

Romance........... .

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I need help proving this ASAP

Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

$\tan(x + \frac{3\pi}{2} ) = - \cot \: x$

One way is to use the basic double angle formula:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ \sin(x) \cos( \frac{3\pi}{2} ) + \cos(x) \sin( \frac{3\pi}{2}) }{\cos(x) \cos( \frac{3\pi}{2} ) - \sin(x) \sin( \frac{3\pi}{2}) }$

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ \sin(x) ( 0) + \cos(x) ( - 1) }{\cos(x) (0) - \sin(x) ( - 1) }$

We simplify further to get:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ 0 - \cos(x) }{0 + \sin(x) }$

We simplify again to get;

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{- \cos(x) }{ \sin(x) }$

This finally gives:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = - \cot(x)$

6 0

4 years ago

Answer this math quedtion <br> 40s+(2b)s+200

Elina [12.6K]

Is it supposed to be equal to something, maybe "0"? You wouldn't be able to solve this without that.

5 0

3 years ago

Group the first two terms by underline the first two terms 16x^3-4x^2-4x+1

Daniel [21]

Answer:

Terms are the things that are separated by a (+) or a (-).

Step-by-step explanation:

<u>16x^3</u> - <u>4x^2</u> -4x+1

I don't think I'm right...

7 0

3 years ago

Given the arithmetic sequence an = 2 + 4(n − 1), what is the domain for n?

zlopas [31]

The answer should be A the first one

3 0

4 years ago

Read 2 more answers

A=1/2h(B+b); A=45, B=4, b=5

klemol [59]

Answer: h=10

Solving Steps:
45 = 1/2h x (4+5)
45 = 1/2h x 9
45 = 9/2h
10 = h
h = 10

4 0

4 years ago