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Dimas [21]
3 years ago
12

Select all the descriptions that apply to the transformation.

Mathematics
1 answer:
Pavel [41]3 years ago
4 0

Answer:

  • B and D

Step-by-step explanation:

As we see the transformation involves translation left and down by 6 units

<u>Correct answer choices are:</u>

  • B. 6 units down, 6 units left
  • D. T(-6, -6)
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The mean one-way commute to work in Chowchilla is 7 minutes. The standard deviation is 2.4 minutes, and the population is normal
adell [148]

Answer:

The answer is below

Step-by-step explanation:

Given that:

The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z=\frac{x-\mu}{\sigma}

a) For x < 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

From normal distribution table,  P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%

b) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337  

c) For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table,  P(x < 11) = P(z < 1.67) = 0.9525

d) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) =  0.2033- 0.0188 = 0.1845  

e) For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table,  P(x < 5) = P(z < -0.83) = 0.2033

8 0
4 years ago
What is 2(x + 4)=2(-8- x) - 2x
Maru [420]

Answer:

You want to solve for x, the first thing you need to do is distribute

The 2 through the x+4 then the other 2 through the -8-x

2(x+4)= 2x+8

2(-8-x)= -16-2x

2x+8=-16-2x-2x (combine like terms on the right side)

2x+8=-16-4x (now subtract 8 from each side)

2x=-24-4x (8-8=0, -16-8=-24) (now add 4x to each side)

6x=-24 (-4x+4x=0, 2x+4x=6x), (divide each side by 6)

x=-4 (6/6=1, -24/6=-4)

x=-4

Hope this helps ;)

6 0
4 years ago
Given RT below, if S lies on RT such that the ratio of RS to ST is 3:1, find the coordinates of S.
Ksivusya [100]

Answer:

S(-2, -3)

Step-by-step explanation:

Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;

S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;

x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1

Substitute the values into the formula;

X = ax2+bx1/a+b

X = 3(-1)+1(-5)/3+1

X = -3-5/4

X = -8/4

X = -2

Similarly;

Y = ay2+by1/a+b

Y = 3(-5)+1(3)/3+1

Y = -15+3/4

Y = -12/4

Y = -3

Hence the coordinate of the point (X, Y) is (-2, -3)

5 0
3 years ago
ABC Office Supply offers an electric typewriter for $129.95. If ABC received a 15% markup on cost by selling the typewriter at t
const2013 [10]
A 15% percent markup means that the typewriter cost was increased by 15%, or 0.15 by moving the decimal 2 places to the left. If the original price was x, and 15% of it is 0.15*x, we can add them up to get 1.15*x=129.95. Dividing both sides by 1.15, we get x=113 dollars
8 0
3 years ago
Read 2 more answers
According to ​Lambert's law​, the intensity of light from a single source on a flat surface at point P is given by Upper L equal
malfutka [58]

Answer:

(a) L = k*(1 - sin^{2}(\theta))        

(b) L reaches its maximum value when θ = 0 because cos²(0) = 1

Step-by-step explanation:

Lambert's Law is given by:

L = k*cos^{2}(\theta)   (1)

(a) We can rewrite the above equation in terms of sine function using the following trigonometric identity:

cos^{2}(\theta) + sin^{2}(\theta) = 1

cos^{2}(\theta) = 1 - sin^{2}(\theta)  (2)

By entering equation (2) into equation (1) we have the equation in terms of the sine function:

L = k*(1 - sin^{2}(\theta))        

(b) When θ = 0, we have:

L = k*cos^{2}(\theta) = k*cos^{2}(0) = k  

We know that cos(θ) is a trigonometric function, between 1 and -1 and reaches its maximun values at nπ, when n = 0,1,2,3...

Hence, L reaches its maximum value when θ = 0 because cos²(0) = 1.

I hope it helps you!

5 0
3 years ago
Read 2 more answers
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