So, both equations are essentially linear equations.
Linear equations are written in the format
y = mx+b, where
m represents the
slope/slope intercept and
b represents the
y-intercept.
---------------------------------------------------------------------------------------------------------------
Part Athe slope and y-intercept
y = mx +b
m - the slope; b- y-intercept
therefore;
y = 6x - 4
m = 6; b = -4y = 5x - 3
m = 5; b = -3The coordinates of the point where the lines are crossed are the solution to the system of linear equations.
How to graph the lines:
y = 6x - 4
y-intercept (0; -4)
for x = 1 ⇒ y = 6 · 1 - 4 = 6 - 4 = 2 ⇒ (1; 2)
y = 5x - 3
y-intercept (0; -3)
for x=1 ⇒ y = 5 · 1 - 3 = 5 - 3 = 2 ⇒ (1; 2)
***look at the img for graph reference***Part B:
x = 1; y = 2
B and C since in these cases money is leaving your account.
All ratios have to simplified because it’s easier for the person to find the difference when breaking it down into lowest terms!
98 because 10+88=98 so that is you're answer don't forget to rate me pls
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Write the expression below in terms of x and y only:
(I'm going to call it "E")
![\mathsf{E=sin\!\left[sin^{-1}(x)+cos^{-1}(y)\right]\qquad\quad(i)}](https://tex.z-dn.net/?f=%5Cmathsf%7BE%3Dsin%5C%21%5Cleft%5Bsin%5E%7B-1%7D%28x%29%2Bcos%5E%7B-1%7D%28y%29%5Cright%5D%5Cqquad%5Cquad%28i%29%7D)
Let

so the expression becomes

• Finding

![\mathsf{sin\,\alpha=sin\!\left[sin^{-1}(x)\right]}\\\\ \mathsf{sin\,\alpha=x\qquad\quad\checkmark}](https://tex.z-dn.net/?f=%5Cmathsf%7Bsin%5C%2C%5Calpha%3Dsin%5C%21%5Cleft%5Bsin%5E%7B-1%7D%28x%29%5Cright%5D%7D%5C%5C%5C%5C%20%5Cmathsf%7Bsin%5C%2C%5Calpha%3Dx%5Cqquad%5Cquad%5Ccheckmark%7D)
• Finding


because

is positive for
![\mathsf{\alpha\in \left[-\frac{\pi}{2},\,\frac{\pi}{2}\right].}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Calpha%5Cin%20%5Cleft%5B-%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%5C%2C%5Cfrac%7B%5Cpi%7D%7B2%7D%5Cright%5D.%7D)
• Finding

![\mathsf{cos\,\beta=cos\!\left[cos^{-1}(y)\right]}\\\\ \mathsf{cos\,\beta=y\qquad\quad\checkmark}](https://tex.z-dn.net/?f=%5Cmathsf%7Bcos%5C%2C%5Cbeta%3Dcos%5C%21%5Cleft%5Bcos%5E%7B-1%7D%28y%29%5Cright%5D%7D%5C%5C%5C%5C%20%5Cmathsf%7Bcos%5C%2C%5Cbeta%3Dy%5Cqquad%5Cquad%5Ccheckmark%7D)
• Finding


because

is positive for
![\mathsf{\beta\in [0,\,\pi].}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cbeta%5Cin%20%5B0%2C%5C%2C%5Cpi%5D.%7D)
Finally, you get
![\mathsf{E=x\cdot y +\sqrt{1-y^2}\cdot \sqrt{1-x^2}}\\\\\\ \therefore~~\mathsf{sin\!\left[sin^{-1}(x)+cos^{-1}(y)\right]=x\cdot y +\sqrt{1-y^2}\cdot \sqrt{1-x^2}\qquad\quad\checkmark}](https://tex.z-dn.net/?f=%5Cmathsf%7BE%3Dx%5Ccdot%20y%20%2B%5Csqrt%7B1-y%5E2%7D%5Ccdot%20%5Csqrt%7B1-x%5E2%7D%7D%5C%5C%5C%5C%5C%5C%20%5Ctherefore~~%5Cmathsf%7Bsin%5C%21%5Cleft%5Bsin%5E%7B-1%7D%28x%29%2Bcos%5E%7B-1%7D%28y%29%5Cright%5D%3Dx%5Ccdot%20y%20%2B%5Csqrt%7B1-y%5E2%7D%5Ccdot%20%5Csqrt%7B1-x%5E2%7D%5Cqquad%5Cquad%5Ccheckmark%7D)
I hope this helps. =)
Tags: <em>inverse trigonometric trig function sine cosine sin cos arcsin arccos sum angles trigonometry</em>