Using a binomial distribution considering there's a 30% chance it will rain on any of the three days:
<span>The probability of it raining on 0 days is (1)(0.7)(0.7)(0.7) = 34.3%. </span>
<span>The probability of it raining on 1 day is (3)(0.3)(0.7)(0.7) = 44.1%. </span>
<span>The probability of it raining on 2 days is (3)(0.3)(0.3)(0.7) = 18.9%. </span>
<span>The probability of it raining on 3 days is (1)(0.3)(0.3)(0.3) = 2.7%. </span>
<span>There's a 65.7% chance that it will rain at least once over the three-day period.</span>
Answer:
-22
Step-by-step explanation:
1.Factor out the negative sign.
2.Calculate (add for question 18)
3. Add the negative sign back.
Hope this helps :)
Answer:
Step-by-step explanation:
Mean= 9+8+14+12+5+14 divided by 6
which gives you 62 divided by 6
which is 10.33333
rounded to 2 decimal point = 10.33
median= 12 and 14
