Answer: 
<u>Step-by-step explanation:</u>
EQ1: x + y = 12 --> x = 12 - y
EQ2: xy = 15
Substitute x = 12-y into EQ2 to solve for y:
(12 - y)y = 15
12y - y² = 15
0 = y² - 12y + 15
↓ ↓ ↓
a=1 b= -12 c=15

Now, let's solve for x:

Lastly, find x² + y² :



Answer:
The minimum number of fish each must have caught is 90 fishes
Step-by-step explanation:
The number of fishes Tisha's net can hold = 15
The number of fishes Dana's net can hold = 18
Let the total number of fishes both Tisha and Dana caught = X
15 × A = 18 × B = X
Therefore, X is the lowest common multiple (LCM) of 15 and 18 given as follows;
15 = 3 × 5
18 = 3 × 6
Therefore, the LCM of 18 and 5 = 3 × 5 × 6 = 90
Which gives, the minimum number of fish each must have caught = 90 fishes.
Answer:
39.2
Step-by-step explanation:
56 × 7 = 392
392 / 10 = 39.2
Y = mx+b
m= 4
y= 4x+b
solve for b using (6,-1)
-1 = 4 (-1)+b
b=3
therefore equation is y=4x+3
same as (y+1)=4(x-6)
Answer:
n ÷ 2
Step-by-step explanation:
if you insert a 12 for 'n', the corresponding value below would be 12÷2, or 6
this follows the pattern in the table