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Select the following statement that is true about shape a and shape b. Question 12 options: Similar—shape b has been stretched,

vagabundo [1.1K]

Answer:

Not similar -- shape B has been streched, these shapes are neither similar or congruent.

Step-by-step explanation:

4 0

3 years ago

What numbers fall between 4.7 and 4.8 on a number line

SVEN [57.7K]

Answer:

4.71, 4.72, 4.73, 4.74, 4.75, 4.76,4.77, 4.78, and 4.79

Step-by-step explanation:

all you need to do is move into hundredths and you need to know that there are 10 hundredths between 2 tenths.

3 0

2 years ago

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Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt$

Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt$

$\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du$

Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

$r=v+1\implies\mathrm dr=\mathrm dv$

$\mathrm ds=e^v\,\mathrm dv\implies s=e^v$

$\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv$

$\displaystyle=-(2e-1)+(e-1)=-e$

So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

3 0

3 years ago

In the construction of the circumcenter, why do you only need to construct two perpendicular bisectors, and not all three?

Wittaler [7]

We know that the Circumcenter is the intersection of a triangle's right (perpendicular) bisectors. Once you have found two of these you can determine their point of intersection.

It is a proven mathematical concept that the third perpendicular bisector will also cross through this intersection point. While it is not necessary to construct all three it is often done so to verify that the intersection of the first two perpendicular bisectors was in fact correct.

7 0

2 years ago

Hernando's salary was $54,500 last year. This year his salary was cut to $52,355. Find the percent decrease. Round to the neares

Otrada [13]

Answer:

Decrease by 3.9%

Step-by-step explanation:

54,500(1-x) = 52355

x=0.03935... = 3.935% or 3.9%

8 0

2 years ago

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