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Alex
3 years ago
13

A drawer contains 12 brown socks and 12 black socks, all unmatched. A man takes socks out at random in the dark. 21. Required in

formation The least number of socks that he must take out to be sure that he has at least two black socks is _____.
Mathematics
1 answer:
avanturin [10]3 years ago
6 0

Answer:

6  socks

Step-by-step explanation:

What we must do is calculate the probability of this happening, that he takes out two black socks in the first two taken out.

There are 12 black socks and in total they are 24, therefore the probability of drawing 1 is:

12/24

and now the probability of getting another one is 11 (there is one less outside) and in total they are 23:

11/23

the final probability is the multiplication of these events:

(12/24) * (11/23)

P = 0.24

Now, to know how many you should get, we multiply the probability by the total number of socks, that is:

0.24 * 24 = 5.76

So you must take out at least 6 socks for the above to happen.

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8 0
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Helppppp!!!!<br> I don’t understand it
oksian1 [2.3K]
Okay so for 2x-y > 3
Subtract -2 from each side
-y>-2x+3
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And when you divid you gotta switch signs
So it’s y<2x-3

3x-5y less than and equal to 25
Subtract 3
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6 0
2 years ago
Divide 50 into the ratio 1:4
Alex787 [66]
The answer is 10:40 
so 1:4
add it up
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7 0
3 years ago
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HELP ASAP DUE TOMORROW
vesna_86 [32]

Answer:

5) P (arrive) + P (not arrive) = 100%   Complements

80% + P( not arrive) = 100%    Substitute thr ralees

P ( not arraive) = 100% - 80%   Isolate the needed

P ( not arrive) = 20%

therefor, the probability of not arriving on time is:-

20%, or 0.20, or 1/5

The complements of arriving on time is not arriving on time.

The probability is equal to 100%

<u>--------------------------------</u>

<u>hope it helps..</u>

<u>have a great day!</u>

7 0
3 years ago
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