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miss Akunina [59]
3 years ago
10

What is a proportion in math definition ???????????????

Mathematics
1 answer:
miv72 [106K]3 years ago
8 0
A proportion<span> is a name we give to a statement that two ratios are equal. It can be written in two ways: two equal fractions, or, using a colon, a:b = c:d.</span>
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Simplify; 1/x^2+5x+6 + 1/x^2+3x+2<br><br> pls I need a step by step solution urgently
ikadub [295]

Answer:

The simplest form of  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}  is  \frac{2}{(x+1)(x+3)}

Step-by-step explanation:

To add two algebraic fractions do these steps

  1. Factorize each denominator
  2. Simplify each fraction to its lowest term
  3. Find the LCM of the two denominators
  4. Divide LCM by each denominator and multiply the numerators by its corresponding quotients
  5. Add the two fraction and simplify the last answer

To simplify \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}

Factorize each denominator

∵ The denominator of the first fraction is x² + 5x + 6

∵ x² = (x)(x)

∵ 6 = (2)(3)

∵ (2)(x) + (3)(x) = 5x ⇒ middle term

∴ x² + 5x + 6 = (x + 2)(x + 3)

∵ The denominator of the second fraction is x² + 3x + 2

∵ x² = (x)(x)

∵ 2 = (2)(1)

∵ (2)(x) + (1)(x) = 3x ⇒ middle term

∴ x² + 3x + 2 = (x + 2)(x + 1)

Find the LCM of the two denominators

∵ The denominators are (x + 2)(x + 3) and (x + 2)(x + 1)

- LCM is all the <u><em>different factors</em></u> multiplied together

∴ LCM of them is (x + 1)(x + 2)(x + 3)

- Divide LCM by each denominator

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 3) = (x + 1)

- Multiply the numerator of the first fraction by (x + 1)

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 1) = (x + 3)

- Multiply the numerator of the second fraction by (x + 3)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{x+1}{(x+1)(x+2)(x+3)}+\frac{x+3}{(x+1)(x+2)(x+3)}

- Add the numerators and write the answer as a single fraction

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2x+4}{(x+1)(x+2)(x+3)}

- Factorize the numerator by taking 2 as a common factor

∵ 2x + 4 = 2(x + 2)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2(x+2)}{(x+1)(x+2)(x+3)}

- Simplify the fraction by dividing up and down by (x + 2)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2}{(x+1)(x+3)}

The simplest form of  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}  is  \frac{2}{(x+1)(x+3)}

5 0
3 years ago
Area of Rectangles and Squares.<br> Please show the work, I need help
USPshnik [31]

Here, I think I can help you out:

1. 21 ÷ 3

= 7

Therefore, the length is 7cm².

2. 35 ÷ 7

= 5cm²

- And so on. Simply divide the area by the length of the side given; you can answer up to question six using this strategy.

7. All sides of a square are the same length.

7 x 7

= 49cm²

9. 2 x 3.5

= 7m²

- The formula to find the area of a square/rectangle is length x width. Just multiply the given lengths for the answers :)

7 0
2 years ago
Read 2 more answers
Ill give brainliest just please hurry :)
Pie
Y=1:5x is the forest answer i hope this helps
7 0
3 years ago
Classify the function as linear or quadratic and identify the quadratic, linear, and constant terms. y=(3x+4)(-2x-3)
MissTica
Y=(3x+4)(-2x-3)=-6x^2-4x-9x-12=-6x^2-13x-12.
It is a quadratic function because it has x in power 2 (x^2)
3 0
3 years ago
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Graph the line for y+1 = - 3(2x - 4) on the coordinate plane.​
Vika [28.1K]
Slope = -6
Y-intercept = (0,11)
X Y
0 11
1 5
3 0
2 years ago
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