2 years ago

Write the Equation of the line that is parralel to the linear equation in question 1 and passes through the point (3,7)

1 answer:

4 0

Where’s question 1? And the question

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emmainna [20.7K]

Answer:

$y= 3x+17; y= -\frac13x +\frac{11}3$

Step-by-step explanation:

First problem. If you want a parallel to a given line, you keep the slope.

Then we use the point-slope form of a line

$y-y_0=m(x-x_0)$ and we plug in there everything we need.

$y-5=3(x+4) \rightarrow y=3x+12+5\\y=3x+17$

The second is quite similar. This time we want the perpendicular. It means that the product of the slopes has to be -1.

$3\cdot m = -1 \rightarrow m=-\frac13$

At this point we have everything, let's replace and write down the line in a better looking form

$y-5=-\frac13(x+4) \rightarrow y= -\frac13 x -\frac43 +5\\y= -\frac13x -\frac43 +\frac{15}3 \rightarrow y= -\frac13x +\frac{11}3$

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2 years ago

Anna11 [10]

3 * (3/4 + 2/6) = 3 1/4

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2 years ago

maxonik [38]

1/3 - 1/6
= 2/6 - 1/6
= 1/6

so, 1/3 - 1/6 = 1/6

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2 years ago

solniwko [45]

The interquartile range is A. 15.5

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3 years ago

Dafna11 [192]

4 + 5 + 3 + 5 = 17

The jogger ran 17 miles in all.

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3 years ago