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AnnyKZ [126]
3 years ago
12

I really need help here I don’t know how to do this

Mathematics
1 answer:
sattari [20]3 years ago
7 0

Answer:

Second box for Justifications: Subtraction Property of equality

Third box for steps: \frac{2}{3} y=-6

Fourth box for steps: \frac{2}{3} y*\frac{3}{2} =-6*\frac{3}{2}

Fourth box for Justifications: Multiplication Property of equality

Fifth box for steps: y=-9

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400cm

Step-by-step explanation:

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(2x + 3) + (4x + 5)<br> please help im really confused
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6 0
2 years ago
Bob wants $50,000 at the end of 7 years in order to buy a car. if his bank pays 4.2% interest, compounded annually, how much mus
Furkat [3]
<span>The correct answer is $1452.50 per year.

Explanation:<span>
We use the formula
</span></span>P(1+\frac{r}{n})^{nt}+PMT(\frac{[(1+\frac{r}{n})^{nt}-1]}{\frac{r}{n}})\times (1+\frac{r}{n}),<span><span>

where P is the amount of principal invested, r is the interest rate as a decimal number, n is the number of times per year the interest is compounded, PMT is the monthly deposit added, and t is the number of years.

Since the amount of principal is not stated, we will assume that Bob is depositing the same amount every following year as he does the first year, so we will let PMT=P.

Our interest rate, r, is 4.2%; 4.2%=4.2/100=0.042.

The number of times the interest is compounded annually, n, is 1.
The amount of time, t, is 7.

We know he wants $50,000. This gives us the equation
50000=P(1+0.042/1)</span></span>⁽¹ˣ⁷⁾<span><span>+P{[(1+0.042/1)</span></span>⁽¹ˣ⁷⁾<span><span>]/(0.042/1)}*(1+0.042/1).

Simplifying this a bit, we have
50000=P(1.042)</span></span>⁷<span><span>+P((1.042</span></span>⁷<span><span>)/0.042)*(1.042).

We can factor out P, giving us
50000=P[1.042</span></span>⁷<span><span>+((1.042</span></span>⁷<span><span>)/0.042)*1.042].

This then gives us
50000=P(34.4234).

Divide both sides:
50000/34.4234 = (P(34.4234))/34.4234,

which gives us P=1452.50.</span></span>
4 0
3 years ago
Read 2 more answers
How old are the property
cricket20 [7]
You didn't enter a valid question. 
7 0
3 years ago
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