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sergiy2304 [10]
3 years ago
11

On Mars, 3 bags of MartianMallows cost 24 space rocks. If each bag contains 10 MartianMallows, how many space rocks does four Ma

rtianMallows cost? Express your answer as an improper fraction.
Mathematics
1 answer:
harina [27]3 years ago
5 0

Answer:

16/5

Step-by-step explanation:

If each bag contains 10 MartianMallows, then 3 bags contain (3)(10)=30 MartianMallows. Since we know that the cost of 30 MartianMallows is 24 space rocks, we can set up the proportion 24/30=s/4, where s is the cost of four MartianMallows. Solving for s, we find that s=24/30*(4)={16/5 space rocks.

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The answer because I need a lot of help and I tried to do it but I need to see the answer first<br>​
zavuch27 [327]

Answer:

number 2 is 140, number 4 is 25.35,number 6 is 249.1

4 0
3 years ago
If a car has traveled 171 miles in 3 hours at a steady pace, how far has it traveled each hour?
san4es73 [151]

Answer:

B: 57 mph=57 mph

Step-by-step explanation:

A steady pace means constant speed  that it does not change over a period of time and direction of motion. A simple formula, for this case (constant speed)

v= \frac{x - xo}{t -to}

where x is distance and t time. The subtract is final value minus initial value

We have the distance and time, then

v= \frac{171 miles}{3 hours}  = 57 mph

7 0
3 years ago
4.23×10 to the third power in standard notation/4.23×10 to the third power equals 4.23 times blank equals blank
vredina [299]

9514 1404 393

Answer:

  4230

Step-by-step explanation:

  4.23×10³ = 4.23×<u>1000</u> = <u>4230</u>

6 0
3 years ago
A lawn sprinkler sprays water 4 feet in all direction as it rotates.
Ber [7]

Answer:

50.24 ft^2

Step-by-step explanation:

The radius of the circle in which the lawn sprinkler sprays water is 4 feet.

The formula to find the area of a circle is \pi r^2, where r = radius and π, in this case, is 3.14.

  • 3.14 × 4^2
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Therefore, the answer is 50.24 ft².

5 0
2 years ago
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

---------------------------------------------------------------------------------------

(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0
3 years ago
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