Answer:
70
Step-by-step explanation:
28 +24+18
=70
answer is 70
Pythagorean TheoremIn a right triangle, the sum of the squares of the legs equals the square of the hypotenuse."Special Triangles"<span>3-4-5
5-12-13
7-24-25
8-15-17</span>Converse of the Pythagorean ConjectureIf the lengths of a triangle satisfy the Pythagorean Theorem, then the triangle is a right triangle.Isosceles Right Triangle ConjectureIn an isosceles right triangle, if the legs have length x, then the hypotenuse has length x-root-2.30-60-90 Triangle ConjectureIn a 30-60-90 triangle, if the shorter leg has length x, then the longer leg has length x-root-3 and the hypotenuse has length 2x.Rationalizing the DenominatorEquation for a Circlea squared + b squared is less than c squaredObtuse trianglea squared + b squared is greater than c squaredAcute triangle
It’s c (plane) if your asking for two-dimensional set of points
Answer: 
Step-by-step explanation:
Since, According to the question,
The chance of finding a bug in a program = 18%
Thus, the probability of finding the bug in first attempt = 
⇒ The probability of not finding any bug in first attempt = 
Similarly, in second attempt , third attempt, fourth attempt_ _ _ _ _ tenth attempt, the probability of not finding any bug is also equal to 
Thus, the probability that she does not find a bug within the first 10 programs she examines
= 
= 
Answer:
Explicit formula is
.
Recursive formula is 
Step-by-step explanation:
Step 1
In this step we first find the explicit formula for the height of the ball.To find the explicit formula we use the fact that the bounces form a geometric sequence. A geometric sequence has the general formula ,
In this case the first term
, the common ratio
since the ball bounces back to 0.85 of it's previous height.
We can write the explicit formula as,

Step 2
In this step we find the recursive formula for the height of the ball after each bounce. Since the ball bounces to 0.85 percent of it's previous height, we know that to get the next term in the sequence, we have to multiply the previous term by the common ratio. The general fomula for a geometric sequene is 
With the parameters given in this problem, we write the general term of the sequence as ,
