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Kryger [21]
3 years ago
15

An exhibition was open for one weekend only. On the Saturday, there were 360 visitors to the exhibition. There were 15% fewer vi

sitors on the Sunday than there were on Saturday. Work out how many visitors there were on the Sunday.
Mathematics
2 answers:
Papessa [141]3 years ago
8 0

Answer:306

Step-by-step explanation:

360×.15= 54

360-54= 306

Marysya12 [62]3 years ago
3 0

Answer:

306 Hope it helps :3

Step-by-step explanation:

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The ratio of Red Apples to Green Apples is 5:2. The proportion of red apple is 5/7.

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So the combined amount of red and green apples sold = No of red apples sold divided by the proportion of red apples = 45/ (5/7) = 63

The combined amount of red and green apples sold is 63 apples.

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What is the rule when finding the sum of numbers from 1-100?
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An art history professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below
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Answer:

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 79.7 and a standard deviation of 8.4.

This means that \mu = 79.7, \sigma = 8.4

B: Scores below the top 13% and above the bottom 56%

So between the 56th percentile and the 100 - 13 = 87th percentile.

56th percentile:

X when Z has a p-value of 0.56, so X when Z = 0.15. Then

Z = \frac{X - \mu}{\sigma}

0.15 = \frac{X - 79.7}{8.4}

X - 79.7 = 0.15*8.4

X = 81

87th percentile:

X when Z has a p-value of 0.87, so X when Z = 1.13.

Z = \frac{X - \mu}{\sigma}

1.13 = \frac{X - 79.7}{8.4}

X - 79.7 = 1.13*8.4

X = 89

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

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