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barxatty [35]
3 years ago
9

absmiddle" class="latex-formula">
Mathematics
1 answer:
sergeinik [125]3 years ago
4 0

Answer:

The answer is 72

Step-by-step explanation:

3x(4 + 8)x2

=3 x 12 x 2

=36 x 2

=72

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Help please in need help help
Zanzabum
The value of x is zero
5 0
3 years ago
Read 2 more answers
WILL GIVE BRAINEST <br>find f(-2) for f(x)=2×3^x<br>a.-18<br>b.1/18<br>c.-36<br>d.2/9
-BARSIC- [3]
D is correct. f(-2) the number in the bracket is an input so..
whenever you see an X in the function replace it with -2
f(-2)=2*3^-2
3^-2 is 1/9
1/9 * 2 is simply 2/9
so D is correct
5 0
4 years ago
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Jane paid $35 for her meal. If the cost of the meal was $30 , what was the tax rate.
Harman [31]

Answer:

L-M-F-A-O-A-O-A-O-A SHERSI LOOK AT YOU CHEATING BYE- IM DONE

Step-by-step explanation:

7 0
3 years ago
Find the output, y, when the input, r, is 30.<br> y = 14 – 0.52
Iteru [2.4K]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberr
Veseljchak [2.6K]

Answer:

<em>The calculated value |t| = 2.375 > 2.1009  at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>Alternative hypothesis is accepted</em>

<em>The extra carbonation of cola results in a higher average compression strength</em>

<u><em /></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given data</em>

<em>First sample size (n₁) = 10 </em>

<em>mean of the first sample(x₁⁻) = 537</em>

<em>standard deviation of the first sample (S₁) = 22</em>

<em>second sample size (n₂) = 10 </em>

<em>mean of the second sample (x₂⁻) = 559</em>

<em>standard deviation of the second sample (S₂) = 17</em>

<u><em>Step(ii)</em></u><em>:-</em>

<u><em>Null hypothesis : H₀:</em></u><em>- The extra carbonation of cola results in a lower average compression strength</em>

<u>Alternative Hypothesis :H₁</u>

<em>The extra carbonation of cola results in a higher average compression strength</em>

<u><em>Step(iii)</em></u><em>:-</em>

<em>By using student's t -test for difference of means</em>

<u><em>Test statistic</em></u>

<em>       </em>t = \frac{x^{-} _{1}-x^{-} _{2}  }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} }  } )}<em />

<em>  where </em>

<em>     </em>S^{2}  = \frac{n_{1}S^{2} _{1} + n_{2} S_{2} ^{2}  }{n_{1}+n_{2} -2 }<em />

<em>    </em>S^{2}  = \frac{10(22)^{2}  + 10 (17) ^{2}  }{10+10 -2 } = \frac{ 7730}{18} = 429.4<em />

<em>    </em>t = \frac{537-559 }{\sqrt{429.4 (\frac{1}{10 }+\frac{1}{10 }  } )}<em />

<em>   t =  -2.375</em>

<em>|t| = |-2.375| = 2.375</em>

<em>Degrees of freedom</em>

<em>γ = n₁+n₂ -2 = 10+10-2 =18</em>

<em />t_{\frac{\alpha }{2} ,n-1}=t_{(\frac{0.05}{2} ,18)} = t_{(0.025,18)}}=2.1009<em />

<em>The calculated value |t| = 2.375 > 2.1009  at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>Alternative hypothesis is accepted</em>

<u><em>Final answer:-</em></u>

<em>The extra carbonation of cola results in a higher average compression strength</em>

<u><em /></u>

<em />

<em> </em>

<em />

5 0
3 years ago
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