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Marina CMI [18]
3 years ago
14

About 9% of the population of a large country is hopelessly romantic. If two people are randomly selected, what is the probabili

ty both are hopelessly romantic? What is the probability that at least one is hopelessly romantic?
A) The probability that both will be hopelessly romantic is _________. (Round 4 decimal places as needed).
B) The probability that at least one person is hopelessly romantic is _______.
Mathematics
1 answer:
ad-work [718]3 years ago
8 0

Answer:

A. 0.0081

B. 0.1638

Step-by-step explanation:

From the question, we are told that 9% of the population are hopelessly romantic.

The percentage that are not hopelessly romantic = 100-9 = 91%

The probability of choosing a hopelessly romantic person = 9% = 9/100 = 0.09

The probability of choosing a person who is not hopelessly romantic = 91% = 91/100 = 0.91

Now, we want to select two people and calculate the following probability;

1. Both will be hopelessly romantic

Let’s have the people as A and B

The probability that both will be hopelessly romantic will the the product of being hopelessly romantic probability = 0.09 * 0.09 = 0.0081

b. Probability that at least one person is hopelessly romantic

What this means is that the probability that one of the two ONLY is hopelessly romantic;

We can have two cases here;

Probability (That A is hopelessly while B is not )or Probability (A is not and B is hopeless )

Thus we have :

(0.09 * 0.91) + (0.91 * 0.09) = 0.0819 * 2 = 0.1638

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Answer:

Following are the true statements

2. The factors common to 20a and 15ab are 1, 5, and a.

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Step-by-step explanation:

Expression is  20a + 15ab + 24b

Now lets have a look at each of the options provided!

1. The factors common to 20a and 15ab are 1, 5, a, and b.

False

As you can see there is no b in 20a term only 1,5,a are common hence it is false.

2. The factors common to 20a and 15ab are 1, 5, and a.

True

The terms 20a and 15ab are divisible by 1,5,a hence it is true.

3. The factors common to 20a and 24b are 1, 2, and 4.

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The terms 20a and 24b are divisible by 1,2,4 hence it is true

4. The GCF of the expression is ab.

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20a + 15ab + 24b

As you can see ab is not common in all of the terms hence it cannot be greatest common factor

5. The GCF of the expression is 1

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Answer:

The answer to your question is Katie had 15 rocks and Oliver 45 rocks.

Step-by-step explanation:

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Oliver has 3x amount of rocks

The final amount of rocks

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Conclusions

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