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docker41 [41]
3 years ago
6

Find the areas of the trapezoid Due soon! I WILL GIVE BRAINLIEST!! WORTH 46 points (92 total)

Mathematics
2 answers:
posledela3 years ago
7 0

Answer:

7.5 sq units

Step-by-step explanation:

Step2247 [10]3 years ago
6 0

Answer:

Solution given

side 1:1 units

side 2=4 units

height =3 units

we have

Area of trapezoid =½*height(side1+side2)

=½*3(1+4)=15/2

<u>areas of the </u><u>trapezoid</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u>/</u><u>2</u><u> </u><u>or</u><u> </u><u>7</u><u>.</u><u>5</u><u> </u><u>square</u><u> </u><u>units</u><u>.</u>

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A soda costs $1.25 in a vending machine. A 12-pack of the same soda costs $3.49 at a grocery store. How much do you save by buyi
sweet [91]

Answer:

you would save 11.51 dollars

Step-by-step explanation:

12 cans times the vending machine price of 1.25$= $15

15-3.49=11.51

5 0
3 years ago
Events A1, A2 and A3 form a partiton of the sample space S with probabilities P(A1) = 0.3, P(A2) = 0.5, P(A3) = 0.2.
timurjin [86]

Answer:

Step-by-step explanation:

Given that events A1, A2 and A3 form a partiton of the sample space S with probabilities P(A1) = 0.3, P(A2) = 0.5, P(A3) = 0.2.

i.e. A1, A2, and A3 are mutually exclusive and exhaustive

E is an event such that

P(E|A1) = 0.1, P(E|A2) = 0.6, P(E|A3) = 0.8,

P(E) = P(A_1E)+P(A_2E)+P(A_3E)\\= \Sigma P(E/A_1) P(A_1) \\= 0.1(0.3)+0.5(0.6)+0.8(0.2)\\= 0.03+0.3+0.16\\= 0.49

P(A_1/E) = P(A_1E)/P(E) = \frac{0.3(0.1)}{0.49} \\=0.061224

P(A_2/E) = P(A_2E)/P(E) = \frac{0.5)(0.6)}{0.49} \\=0.61224

P(A_3/E) = P(A_3E)/P(E) = \frac{0.2)(0.8)}{0.49} \\=0.3265

4 0
3 years ago
A certain circle can be represented by the following equation. x^2+y^2+6y-72=0 What is the center of this circle ?
jek_recluse [69]

Answer:

(0, -3)

Step-by-step explanation:

Here we'll rewrite x^2+y^2+6y-72=0 using "completing the square."

Rearranging x^2+y^2+6y-72=0, we get  x^2 + y^2 + 6y                = 72.

x^2 is already a perfect square.  Focus on rewriting y^2 + 6y as the square of a binomial:  y^2 + 6y becomes a perfect square if we add 9 and then subtract 9:

x^2 + y^2 + 6y + 9  - 9              = 72:

x^2 + (y + 3)^2 = 81

Comparing this to the standard equation of a circle with center at (h, k) and radius r,

(x - h)^2 + (y - k)^2 = r^2.  Then h = 0, k = -3 and r = 9.

The center of the circle is (h, k), or (0, -3).

8 0
3 years ago
I need help on number 1
ollegr [7]
2.5. is the answer. ..
7 0
3 years ago
Read 2 more answers
Caroline purchased a car four years ago at a price of $28,400. According to research on this make and model, similar cars have s
gogolik [260]

Answer:

The car value is $13,312.50

Step-by-step explanation:

Trust me this stuff is easy

3 0
3 years ago
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