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2 years ago

Find the areas of the trapezoid Due soon! I WILL GIVE BRAINLIEST!! WORTH 46 points (92 total)

Mathematics

2 answers:

posledela2 years ago

7 0

Answer:

7.5 sq units

Step-by-step explanation:

Step2247 [10]2 years ago

6 0

Answer:

Solution given

side 1:1 units

side 2=4 units

height =3 units

we have

Area of trapezoid =½*height(side1+side2)

=½*3(1+4)=15/2

areas of the trapezoid is 15/2 or 7.5 square units.

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James bought Nicole a pair of shoes for $54.99 and a bracelet for $21.99. He used a 15% off coupon and then paid 7.5% sales tax.

mina [271]

Answer:

$70.34

Step-by-step explanation:

The total before the coupon and tax is:

$54.99 + $21.99 = $76.98

Now apply the 15% coupon:

Since the total price is 100% of the price, when you apply a 15% coupon, you pay 100% - 15% = 85% of the price. We need to find 85% of $76.98

85% * $76.98 =

= 0.85 * $76.98

= $65.43

The price after the 15% coupon, but before the tax, is $65.43

Now the total $65.43 is considered 100% of the price. The tax is 7.5%.

100% + 7.5% = 107.5%

Now we find 107.5% of $65.43

107.5% of $65.43 =

= 1.075 * $65.43

= $70.34

Answer: $70.34

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2 years ago

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1. 1/2

2. Across Y axis

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5 0

2 years ago

In a kitchen there are three containers that can hold different quantities of water, as shown in the figure below:

elena55 [62]

Answer:

3x-15

Step-by-step explanation:

(x-10)+(x-5)+(x)=3x-15

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2 years ago

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Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and t

WINSTONCH [101]

Answer:

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.

How long will it take for this population to grow to a hundred rodents? To a thousand rodents?

Step-by-step explanation:

Use the initial condition when dp/dt = 1, p = 10 to get k;

$\frac{dp}{dt} =kp^2\\\\1=k(10)^2\\\\k=\frac{1}{100}$

Seperate the differential equation and solve for the constant C.

$\frac{dp}{p^2}=kdt\\\\-\frac{1}{p}=kt+C\\\\\frac{1}{p}=-kt+C\\\\p=-\frac{1}{kt+C} \\\\2=-\frac{1}{0+C}\\\\-\frac{1}{2}=C\\\\p(t)=-\frac{1}{\frac{t}{100}-\frac{1}{2} }\\\\p(t)=-\frac{1}{\frac{2t-100}{200} }\\\\-\frac{200}{2t-100}$