Answer:
x = 12
Step-by-step explanation:
Angle QPR + Angle PQR = Angle HRQ
Answer:
3
−
2
=
1
3v-2=1
3v−2=1
Solve
1
Add
2
2
2
to both sides of the equation
3
−
2
=
1
3v-2=1
3v−2=1
3
−
2
+
2
=
1
+
2
3v-2+{\color{#c92786}{2}}=1+{\color{#c92786}{2}}
3v−2+2=1+2
2
Simplify
Add the numbers
Add the numbers
3
=
3
3v=3
3v=3
3
Divide both sides of the equation by the same term
3
=
3
3v=3
3v=3
3
3
=
3
3
\frac{3v}{{\color{#c92786}{3}}}=\frac{3}{{\color{#c92786}{3}}}
33v=33
4
Simplify
Solution
=
1
Step-by-step explanation:
This is so easy just do 2.25 - 1.50 and u get = 0.75 hope this helps
Answer: y=-7x-45
Explanation: Two parallel lines have the same slope, so that means the slope of the line would be -7. When you add that value to your equation, that would give you: y=-7x+b. Now that you have the slope, the only other value you’re missing is b. To find the value of b, you can substitute any point into the equation that’s on the line and solve for b:
-3=-7(-6)+b
-3=42+b
b=-45
Now that you have the value of b, substitute it into the final equation:
y=-7x-45
Hope this helps シ
9514 1404 393
Answer:
28 hours
Step-by-step explanation:
Let x represent Jack's time. Then Jill's is x-7. Together their rate of carrying water in hills per hour is ...
1/x + 1/(x -7) = 1/12
Multiplying by 12x(x -7) gives ...
12(x -7) +12x = x(x -7)
x^2 -31x +84 = 0 . . . . . subtract the left side and simplify
(x -3)(x -28) = 0 . . . . . . . . . . factor
x = 3 or x = 28 . . . . . . . . . . x-values that make the factors zero
We know the times must be longer than 12 hours, so the value x=3 is extraneous for this problem.
It takes Jack 28 hours to carry the cooler of water up the hill working alone.
