Answer:
(A.) (- 4.33, 6.33 , 0); (B.) (- 3.66, 7.5, 0); (C.) average at (A) (- 4.33, 6.33 , 0) ; (D.) (- 0.2165, 0.3165, 0)
Explanation:
Given the following :
Time - - - - - - - 6.6s - - - - - - - - - 6.9s - - - - - 7.2s
Position - (1.8,5.0,0) - (0.5,6.9,0) - - (−0.4,9.5,0)
(a) Between 6.6 s and 6.9 s, what was the bee's average velocity?
Vavg = Distance / time
[(0.5,6.9,0) - (1.8,5.0,0)] / 6.9 - 6.6
Vavg = [(0.5 - 1.8), (6.9 - 5.0), (0 - 0)] / 0.3
Vavg = - 1.3 / 0.3, 1.9/0.3, 0/3
Vavg = (- 4.33, 6.33 , 0)
b) Between 6.6 s and 7.2 s, what was the bee's average velocity?
Vavg = [(−0.4,9.5,0) - (1.8,5.0,0)] / 7.2 - 6.6
Vavg = - 2. 2/0.6, 4.5/0.6, 0/0.6
Vavg = (- 3.66, 7.5, 0)
c.) Of the two averages (- 4.3, 6.3 , 0) is closer to the instantaneous Velocity at 6.6s
D.) (d) Using the best information available, what was the displacement of the bee during the time interval from 6.6 s to 6.65 s?
Displacement = Velocity * time
Vavg between 6.6 to 6.9 ; time = (6.65 - 6.6) = 0.05 s
= (- 4.33, 6.33 , 0) * 0.05
= (- 0.2165, 0.3165, 0)
