Answer:
x
2
+
2
x
−
15
Step-by-step explanation:
Hello there!
Sense this is a 360 degree angle, it is divide by 2. This would then be considered 180. If you (noticed) on the other side, it shows us that . . .
We then do (180-19)
Answer:
Step-by-step explanation:
perp. -1/2
y + 3 = -1/2(x - 3)
y + 6/2 = -1/2x + 3/2
y = -1/2x - 3/2
Let x be the unknown angle.
Make an equation using the formula.
<span>"measure of one acute angle is 3 times" Since we know that x is the one acute angle, we can multiply that by 3 to get 3x.
"</span><span>the sum of" when ever you see the word 'sum' it means that there will be an addition process involved and in this case it also means that 3x will equal to the rest of the equation. (3x=)
</span>
<span>"measure of the other acute angle and 8" We already know that the other angle is x . Since there is no other indicator of the 8 being subtracted, multiplied, and divided and that we know this is an addition problem, we can conclude that 8 will be added to the other angle. (x+8)
</span>
So, now we have the equation and all we have to do is simplify it.
3x= x+8
-x -x *Move constants and variables to opposite sides*
------------
2x=8
--- --- *Divide by 2 to isolate the variable*
2 2
x=4
So, I'm assuming you want to know the measure of both angles. All you have to do is plug in the x in the 3x and x+8 depending on which angle you want.
3x
3(4)=12
The measure of the first angle is 12.
x+8
4+8= 12
The measure of the second angle is also 12.
Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
The standard deviation, σ, is related to the interquartile range by
IQR = 1.35
From the data, we can say the following:
Movies:
Range = 150 - 60 = 90 (approx)
Q1 = 62 (approx), first quartile
Q3 = 120 (approx), third quartlie
Q2 (median) = 90 (approx)
IQR = Q3 - Q1 = 58
σ = IQR/1.35 = 58/1.35 = 43
Basketball:
Range = 150 - 90 = 60 approx
Q1 = 95 (approx)
Q3 = 145 (approx)
Q2 = 125 (approx)
IQR = 145 - 95 = 50
σ = 50/1.35 = 37
Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
D. The standard deviation is a good measure of spread for both movies and basketball. This is the best answer.
Answer: D
