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2 years ago

Y=-2|x+2|-4 i need to find y intercept and the x intercept

Mathematics

1 answer:

NeTakaya2 years ago

3 0

Answer:

x-int: ∅

y-int: (0,-8)

Step-by-step explanation:

To find the x and y-intercept, simply plug in zero for x and y:

$0=-2|x+2|-4\\4=-2|x+2|\\-2=|x+2|\\$

Because an absolute value cannot be equal to a negative, there is no x-intercept.

$y=-2|0+2|-4\\y=-2|2|-4\\y=-4-4\\y=-8$

Hope it helps :)

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Answer:

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2 years ago

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Step-by-step explanation:

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3 years ago

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you are riding a bicycle which has tires with a 25-inch diameter at a steady 15-miles per hour, what is the angular velocity of

motikmotik

Answer:

The angular velocity is 6.72 π radians per second

Step-by-step explanation:

The formula of the angular velocity is ω = $\frac{v}{r}$ , where v is the linear velocity and r is the radius of the circle

The unit of the angular velocity is radians per second

∵ The diameter of the tire is 25 inches

∵ The linear velocity is 15 miles per hour

- We must change the mile to inch and the hour to seconds

∵ 1 mile = 63360 inches

∵ 1 hour = 3600 second

∴ 15 miles/hour = 15 × $\frac{63360}{3600}$

∴ 15 miles/hour = 264 inches per second

Now let us find the angular velocity

∵ ω = $\frac{v}{r}$

∵ v = 264 in./sec.

∵ d = 25 in.

- The radius is one-half the diameter

∴ r = $\frac{1}{2}$ × 25 = 12.5 in.

- Substitute the values of v and r in the formula above to find ω

∴ ω = $\frac{264}{12.5}$

∴ ω = 21.12 rad./sec.

- Divide it by π to give the answer in terms of π

∴ ω = 6.72 π radians per second

The angular velocity is 6.72 π radians per second

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2 years ago

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with mean 8.8 inches and standard deviation 2.8 inches.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

Mean of 8.8 inches, thus $\mu = 8.8$ .
Standard deviation of 2.8 inches, thus $\sigma = 2.8$ .

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = -0.675(2.8)$

$X = 6.91$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = 0.675(2.8)$

$X = 10.69$

The IQR is:

$IQR = 10.69 - 6.91 = 3.78$

What is the diameter, in inches, of the smallest tree that is an outlier?

The diameter is 1.5IQR above the 75th percentile, thus:

$10.69 + 1.5(3.78) = 16.36$

The diameter of the smallest tree that is an outlier is of 16.36 inches.

A similar problem is given at brainly.com/question/15683591

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