All categories

2 years ago

15, 16, 20, and 22! PLEASE HELP

Mathematics

2 answers:

Vikentia [17]2 years ago

7 0

The answer for number 16 is 20

Scrat [10]2 years ago

5 0

Number 15 should be 3x+6

You might be interested in

The following scatter plot represents the relationship between a person's weight and the number of calories the person burns in

nydimaria [60]

Answer:

They would be roughly 180 Ibs.

6 0

2 years ago

4. A rectangular field has a perimeter of 300m. What is the area of the field if the length of

USPshnik [31]

Answer:

Step-by-step explanation:

5 0

2 years ago

In 1924, the tempature in Fairfield, Montana, dropped from 63 degrees to 21 in 12 hour. What was the average hourly change in te

Drupady [299]

Find the change
the change is 63-21=42
42 degrees in 12 hours
we want to find xdegrees/1hour
42/12=3.5 degrees per hour

8 0

2 years ago

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

2 years ago

SOMEONE PLS HELP!! its due in 10 minutes

melisa1 [442]

Answer:

option 2 is better( 3 pizza with 30 inches diameter)

Step-by-step explanation:

Area of the large pizza = A=πr^2=962.11 * 2( for two pizzas)=1924.22

Area for small pizza : A=πr^2=706.86*3 pizza=2120.58

your buying more pizza for less price

(there are more than one way to figure the answer)

3 0

2 years ago