Question

PLEASE FIND THE VERTEX OF THIS PARABOLA

Answer 1

Given equation of the parabola y= -5x^2 -10x -13.

We need to apply formla for x-coordinate of the vertex.

x=-b/2a.

For the given equation we have a=-5 and b=-10.

Plugging values of a and b in formula of x-coordinate of the vertex.

x= -(-10)/2(-5)

x= 10/(-10) = -1.

So, we got x-coordinate of the vertex = -1.

Now, we need to plug x=-1 in given equation to find the y-coordinate of the vertex.

Plugging x=-1 in y= -5x^2 -10x -13, equation we get

y=-5(-1)^2-10(-1)-13.

y= -5(1) +10 -13.

y=-5 +10-13.

y=-18+10.

y=-8.

So, we got y-coordinate of the vertex -8.

Therefore, vertex of the parabola is (-1,-8).