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pav-90 [236]
3 years ago
10

Solve each exponential equation 8^x=12143

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0
The answer is x=4.522612
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Which expression represents the correct form for the quotient and remainder, written as partial fractions, of
Oduvanchick [21]

Answer:

  • C)~A+ \frac{B}{x-3} +\frac{c}{(x-3)^2}

Step-by-step explanation:

→ \frac{(7x^2-40x+52)}{(x^2-6x+9)}

→ \frac{7x^2-40x+52}{x^2-2.3x+(3)^2}

→  \frac{7x^2-40x+52}{(x-3)^2}

<u>So, your answer is C</u>

<u></u>----------<u></u>

<u>hope it helps...</u>

<u>have a great day!!</u>

8 0
3 years ago
Please help!!!!!!!!!!!!!!!!!! -3x+2 less than 8
sleet_krkn [62]
-3x+2 < 8
-2 -2
-3 /-3x <6/-3
x >-2

So x>-2
7 0
3 years ago
a system of equations has infinitely many solutions. if 2y – 4x = 6 is one of the equations, which could be the other equation?
deff fn [24]
<span>A system of equations has infinitely many solutions when the two lines representing the equations coincide. i.e. the two equations are the same or a multiple of each other.
2y - 4x = 6
2y = 4x + 6
2y = 2(2x + 3)
y = 2x + 3
-y = -(2x + 3)
-y = -2x - 3
Hence the other equation is -y = -2x - 3</span>
4 0
3 years ago
Read 2 more answers
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
What is the coefficient of n^2 in the sum of -5^4+4n^2-n+5 and 7n^4-5n^3-9n^2+3n+2
pickupchik [31]
Hello :
-5^4+4n^2-n+5  : the coefficient of n^2 is : 4<span>
 7n^4-5n^3-9n^2+3n+2 : </span><span>he coefficient of n^2 is :-9</span>
4 0
3 years ago
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