1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shalnov [3]
3 years ago
15

eqslant 11x - 3" align="absmiddle" class="latex-formula">
solve the inequalities
Mathematics
1 answer:
AURORKA [14]3 years ago
6 0

Answer:

0 ≤x

Step-by-step explanation:

9x-3 ≤11x-3

Subtract 9x from each side

9x-9x-3 ≤11x-9x-3

-3 ≤2x-3

Add 3 to each side

-3+3 ≤2x

0 ≤2x

Divide by 2

0/2 ≤2x/2

0 ≤x

You might be interested in
The following data was collected from a simple random sample of a population.
aivan3 [116]

Answer:

C

Step-by-step explanation:

This problem is analogous to the extraction of 6 elements from a total of 10 elements. It's the same if they are marbles, chips, or in this case, people, as here we don't care about the order of the selection as we only are drawing a sample.

Thus, the problem implies solving the amount of possible combinations of 10 people if we take by 6. There is a formula for this and is:

10 C 6 = 10!(6!4!)

If we operate, knowing that for any number x, x!=x*(x-1)*(x-2)*...*1

10 C 6 = 10!(6!4!) = 10*9*8*7*6*...*1 / [(6*5*...*1) * (4*3*2*1)]

10 C 6 = 10*9*8*7*6! / [(6*5*...*1) * (4*3*2*1)]

We have a 6! multiplying and another dividing, so they get eliminated, and as 4*2=8 and 9=3*3

10 C 6 = 10*9*8*7*/ [(4*3*2*1)] = 10*3*3*8*7*/ [(8*3*1)]

We can eliminate the 8s and one of the 3s on the numerator with the one on the denominator:

10 C 6 = 10*3*7*/1 = 210/1= 210

So, option C

5 0
3 years ago
Sin^2x + sin^2x + cos²x
Nezavi [6.7K]

Answer:

Answer:

A. 2 sinx cosx - 1 + 2 sin^2 x.

Step-by-step explanation:

sin2x = 2 sinx cosx

cos2x = cos^2x - sin^2x

So sin2x - cos2x =  2 sinx cosx - ( cos^2x - sin^2x)

But cos^2 x = 1 - sin^2 x, so we have:

2 sinx cosx - (1 - sin^2 x - sin^2x)

= 2 sinx cosx - 1 + 2 sin^2 x.

7 0
3 years ago
What is the value of X
Afina-wow [57]
The answer is d (180-95) 85+60=145 180-145= 35
4 0
3 years ago
Read 2 more answers
The volume of a cylinder is 525 cm3. The radius of the base of the cylinder is 5 cm. What is the height of the cylinder? The hei
elena-14-01-66 [18.8K]

you do not give a value for PI so I am using 3.14

V=PI x r^2 x H

you know volume and radius so put those into the equation

525 = PI (3.14) x 5^2 x H

525 = 3.14 x 25 x H

525 = 78.5 x H

divide both sides by 78.5

6.687 = H

round off answer as needed 6.7cm or 6.69cm

 NOTE : the answer may vary slightly depending on the value of PI used.

 but this is how you calculate the height.

8 0
3 years ago
Read 2 more answers
Public Service Announcement : For anyone that continues to delete my answers even if their educational/ or correct can STAY MAD.
lozanna [386]

Answer:

You tell them

Step-by-step explanation:

Never stop being postive

6 0
3 years ago
Read 2 more answers
Other questions:
  • Lucia knows the fourth term in a sequence is 55 and the ninth term in the same sequence is 90. Explain how she can find the comm
    10·1 answer
  • How do I Simplify 9(5x)
    12·2 answers
  • A guy wire (a tensioned cable designed to add stability to a free-standing structure) is attached to a telephone pole whose heig
    7·1 answer
  • What is the measure of the angle x?​
    9·1 answer
  • Simplify -|-5 + 2|<br> someone help quick
    9·1 answer
  • In a pie chart the central angle in degrees at the center of the circle is a) 180 b) 360 c) 270 d) 90
    14·1 answer
  • Which of the following would NOT work to make a triangle with the two side<br> lengths of 2 and 6?
    15·2 answers
  • Can you guys plz help me
    11·2 answers
  • Pls help with me maaaaaaaaaaaaaaaaaaaaath
    8·2 answers
  • I can walk at 6km/hr and run at 15km/hr. On a journey I spend as long walking as I do running. If I had walked twice as long on
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!