A bus company charges a fixed amount plus a fee based on the distance traveled. The cost chart for the company is shown: Cost Ch
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There are no real solutions to the quadratic equation.
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Area of a triangle ABC with the given vertices is 3 square units.
Given that, the vertices of a triangle ABC, A(3,-6), B(5,-6), and C(7,–9).
<h3>What is the area of triangle formula in coordinate geometry?</h3>In Geometry, a triangle is a three-sided polygon that has three edges and three vertices. The area of the triangle is the space covered by the triangle in a two-dimensional plane.
Area of a triangle =
Here, (x1, y1) = A(3,-6), (x2, y2) = B(5,-6), and (x3, y3) = C(7,–9)
Now, the area of a triangle = 1/2 (|3(-6+9)+5(-9+6)+7(-6+6)|)
= 1/2 (|3(3)+5(-3)+7(0)|)
= 1/2 (|(9-15)|)
= 1/2 × 6
= 3 square units
Therefore, area of a triangle ABC with the given vertices is 3 square units.
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We are given
Angles α and β are angles in standard position
and
α terminates in Quadrant II
β terminates in Quadrant I
and we have
we can use triangle and find cos(α)
we get
and we have
we can draw triangle
now, we can use formula
now, we can plug values
now, we can simplify it
...............Answer
