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2 years ago

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x??

Mathematics

1 answer:

azamat2 years ago

6 0

$x^2-2x+20=0\implies D=b^2-4ac$ .

There are no real solutions to the quadratic equation.

Hope this helps.

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7. Find the measure of one exterior angle of the regular polygon. Triangle

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Answer:120°

Step-by-step explanation:

sum of exterior angles=360

In a triangle we have 3 exterior angles

Size for each exterior angle=360/3

Size for each exterior angle=120°

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2 years ago

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2 years ago

Read 2 more answers

Find the distance between these points. R(-1,0), S(8,6) V(26) V(85) 3V(13)

Thepotemich [5.8K]

Answer:

The distance is equal to $3\sqrt{13}\ units$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$R(-1,0)\\S(8,6)$

substitute the values

$d=\sqrt{(6-0)^{2}+(8+1)^{2}}$

$d=\sqrt{(6)^{2}+(9)^{2}}$

$d=\sqrt{36+81}$

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Simplify

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4 0

3 years ago

Use the definition mtan=lim

Leokris [45]

(a) mtan refers to the slope of the tangent line. Given f(x) = 9 + 7x ², compute the difference quotient:

$\dfrac{f(x+h)-f(x)}h = \dfrac{(9+7(x+h)^2)-(9+7x^2)}h = \dfrac{(9+7x^2+14xh+7h^2)-9-7x^2}h = \dfrac{14xh+7h^2}h$

Then as h approaches 0 - bearing in mind that we're specifically considering h near 0, and not h = 0 - we can eliminate the factor of h in the numerator and denominator, so that

$m_{\rm tan} = \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \lim_{h\to0}\frac{14xh+7h^2}h = \lim_{h\to0}(14x+7h) = 14x$

and so the slope of the line at P (0, 9), for which we take x = 0, is 0.

(b) The equation of the tangent line is then y = 9.

4 0

2 years ago