Question

A sample of 71 eggs yields a sample mean weight of 2.00 ounces. Assuming that the population standard deviation = 0.590 ounces, find the standard error of the mean in estimating a confidence interval estimate for the true population mean weight at the 95% level of confidence. Round your answer to three decimal places

Answer 1

Answer:

0.070 is the standard error of the mean weight in estimating a confidence interval estimate        

Step-by-step explanation:

We are given the following in the question:

Sample mean, $\bar{x}$ =  2.00 ounces

Sample size, n = 71

Alpha, α = 0.05

Population standard deviation, σ = 0.590 ounces

Formula for standard error =

$S.E=\dfrac{\sigma}{\sqrt{n}}$

Putting values, we get,

$S.E = \dfrac{0.590}{\sqrt{71}} = 0.07002\approx 0.070$

Thus, 0.070 is the standard error of the mean weight in estimating a confidence interval estimate