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denpristay [2]
3 years ago
15

A sample of 71 eggs yields a sample mean weight of 2.00 ounces. Assuming that the population standard deviation = 0.590 ounces,

find the standard error of the mean in estimating a confidence interval estimate for the true population mean weight at the 95% level of confidence. Round your answer to three decimal places
Mathematics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

0.070 is the standard error of the mean weight in estimating a confidence interval estimate        

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} =  2.00 ounces

Sample size, n = 71

Alpha, α = 0.05

Population standard deviation, σ = 0.590 ounces

Formula for standard error =

S.E=\dfrac{\sigma}{\sqrt{n}}

Putting values, we get,

S.E = \dfrac{0.590}{\sqrt{71}} = 0.07002\approx 0.070

Thus, 0.070 is the standard error of the mean weight in estimating a confidence interval estimate

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Answer:

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Step-by-step explanation:

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mel-nik [20]

Answer:

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Step-by-step explanation:

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3 years ago
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Maru [420]

9514 1404 393

Answer:

  D.

Step-by-step explanation:

The wording "when x is an appropriate value" is irrelevant to this question. That phrase should be ignored. (You may want to report this to your teacher.)

When you look at the answer choices, you see that all of them are negative except the last one (D). When you look at the problem fraction, you see that it is positive.

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Your calculator can check this for you.

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If you want to "rationalize the denominator", then multiply numerator and denominator by the conjugate of the denominator. The conjugate is formed by switching the sign between terms.

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<em>Additional comment</em>

We "rationalize the denominator" in this way to take advantage of the relation ...

  (a -b)(a +b) = a² -b²

Using this gets rid of the irrational root in the denominator, hence "rationalizes" the denominator.

We could also have multiplied by (3 -√3)/(3 -√3). This would have made the denominator positive, instead of negative. However, I chose to use (√3 -3) so you could see that all we did was change the sign from (√3 +3).

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