Answer:
Tanks of 15.3081 gallons and larger are considered too large.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

How large does a tank have to be to be considered too large
largest 2%, so at least the 98th percentile.
The 98th percentile is X when Z = 0.98. So it is X when Z = 2.054.




Tanks of 15.3081 gallons and larger are considered too large.
Answer: $869.90 × 12 = $10,438.80.
Step-by-step explanation:
Answer:
B. x=-6 or x=8
Step-by-step explanation:
To solve this, factor the equation x^2-2x-48. Since -48 is negative, one of the factors has to be negative and one has to be positive. Since the coefficient of x is -2, the factors have to sum to -2. Trying factors, we realize that (x-8)(x+6)=0 works. Solving, x-8=0 and x+6=0, or x=8 or x=-6.
For number 2 you start with parenthesis first. 4×2=8. 24-2+8. Then u add 2+8=10. 24-10=14. 14 is your answer for 2.
If you are solving for x, the answer is x=16.