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taurus [48]
2 years ago
9

What is the value of X

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
8 0
\dfrac{6}{9}=\dfrac{x+3}{3+9}\\
\dfrac{2}{3}=\dfrac{x+3}{12}\\
3(x+3)=24\\
x+3=8\\
x=5
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Your coffee bar has two kinds of drink One cup of the first one costs 9 grams of juice , 4 grams of coffee and 3 grams of sugar
VMariaS [17]

Answer:

How many drinks should be sold to get a maximal profit? 468

Sales of the first one = 345 cups

Sales of the second one = 123 cups

Step-by-step explanation:

maximize 1.2F + 0.7S

where:

F = first type of drink

S = second type of drink

constraints:

sugar ⇒ 3F + 10S ≤  3000

juice ⇒ 9F + 4S ≤  3600

coffee ⇒ 4F + 5S ≤  2000

using solver the maximum profit is $500.10

and the optimal solution is 345F + 123S

6 0
3 years ago
Fastest one to answer gets 11 points and marked as brainiest! answer ASAP
MAVERICK [17]

Answer:

0.24 its opposite value is - 0.24

1/4 its opposite value is -1/4

0

-5 its opposite value is 5

240 which is positive and its opposite value is -240

Step-by-step explanation:

hey

from the given statement we can see that question demand is about the opposite values. so

as our first value is 0.24 its opposite value is - 0.24

then move on next value is 1/4

its opposite value is -1/4

0 is a neutral value it neither positive or negative

move on to the next value which is -5 who is already negative

so we take a positive value that is 5

again move to 240 which is positive and its opposite value is -240

Hope it will be brainliest to you

5 0
3 years ago
2 (x + 3) + 5 x = 3 (2 x minus 1)
SashulF [63]

hello

Step-by-step explanation:

3 0
3 years ago
16% of ____ shirts are 44<br> How many shirts are there?
yawa3891 [41]
I don’t know, I forgot how to solve problems like this, look it up
5 0
3 years ago
Read 2 more answers
A= [2, 3; 2, 1], B=[3; 5]. Find AB &amp; BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0
3 years ago
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