The answer is w⁻²/v⁻².
v/w raised to the second power is (v/w)²
(v/w)² = v²/w²
Since xᵃ = 1/x⁻ᵃ, then v²/w² = 1/v⁻²w²
Since 1/xᵃ = x⁻ᵃ, then 1/v⁻²w² = w⁻²/v⁻²
-1 , 1 ..........................................................
The linear function g which has a rate of change of -16 and initial value 600 is; g = -16x + 600.
<h3>What is the linear function which is as described?</h3>
It follows from the task content that the linear expression which is as described by the given verbal description is to be determined.
Since the standard slope-intercept form of a linear function is as given; f(x) = ax + b.
Where, a = slope (rate of change) and b = y-intercept (initial value).
Therefore, the required linear function which is as described is;
g = -16x + 600
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Answer:C.11 in
explanation:Hope I helped:)
Answer:
-13a
Step-by-step explanation:
