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antiseptic1488 [7]

3 years ago

12

The surface area of a closed right circular cylinder whose 5 inches and height is 12 inches is givern approximately by 2x3.1416x

5^2+ 2x3.1416x5x12, evaluate this expression

1 answer:

lakkis [162]3 years ago

4 0

Should be around 6 hopefully

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Step-by-step explanation:

It is required to find the expressions that are equivalent to 4-x. We can also write it as :

Option (b) : (4-x) = 4+(-x)

Option (c) : (4-x) = -x+4

Hence, the correct options are (B) and (C).

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Find all solutions of each equation on the interval 0 ≤ x < 2π.

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Answer:

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How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

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This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

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$u^{2} = 1$ .

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$x = k \pi$ , where $k\in \mathbb{Z}$ (i.e., $k$ is an integer.)

Given that $0 \le x < 2\pi$ ,

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