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2 years ago

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A 35 year old mother realized that her age is twice the sum of her two children's age her son Jose is two year old than her daug

hter Sophia how old are Sophia (x) and Jose (y)

1 answer:

Drupady [299]2 years ago

4 0

Answer:

Step-by-step explanation:

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What type of association does there appear to be between the variables? explain

Nataliya [291]

Where are the variables for the equation?

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3 years ago

Suppose that f(x) is an EVEN function and let the integral f(x) dx from 0 to 1=5 and the integral f(x) dx from 0 to 7 =1. What i

Cerrena [4.2K]

<span>Since it's even, the integral from -7 to -1 is the same as the integral from 1 to 7.
</span><span>think about
x^2 from 0..1,its 1/3
from 0..7 its 7^3/3
from -1..7 its 7^3/3+1/3
</span>
<span>from -7..-1 of x^2 its -1/3+7^3/3 to get this without integrating we just do 7^3/3-1/3 which is the integral from 0..7 minus the integral from 0..1
</span><span>So the integral from 1 to 0 f(x) dx = 5 changes to the integral from 0 to 1 f(x) dx = -5 and you add it to the integral from 0 to 7 which is 1 making -4</span>

4 0

3 years ago

There are 5 exams in a semester. You have scored 77, 90, 85, and 100 on the previous four exams. What must you make on the fifth

siniylev [52]

Answer:

<h2>The correct answer for this question is 78.</h2>

Step-by-step explanation:

The average or mean of any variable or mathematical phenomenon is calculated as the division of the sum of all the numbers or items within the particular variable by the total number of items or numbers within the variable.
In this case, the marks of the 4 exams in the semester are 77,90,85 and 100 respectively.There are total 5 exams in the semester.
Let's suppose that the marks for the 5th exam is x.
Therefore, based on the mathematical formula to compute average or mean,to get an overall average of 86 including all the 5 exams, one has to get:-

$\frac{77+90+85+100+x}{5}=86$

$77+90+85+100+x=430$

$x=430-77-90-85-100$

$x=78$

Hence, based on the above calculations,one has has to get 78 on the 5th exam to obtain an overall average of exactly 86.

5 0

3 years ago

101.24 to the nearest hundredth

BaLLatris [955]

Answer:

101.24

Step-by-step explanation:

101.24 is already to the nearest hundredth place.

To the nearest tenth would be 101.2 and to the nearest digit would be 101

5 0

2 years ago

In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel

Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

Now,

change in sulfur oxide with time i.e $\frac{\textup{dS}}{\textup{dt}}$

differentiating the given relation with respect to time 't'

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = $2\times110P\frac{\textup{dP}}{\textup{dt}}$ + 20

at P = 100 and $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = 2 × 110 × 100 × 10 + 20

or

$2S\frac{\textup{dS}}{\textup{dt}}$ = 220020

or

$\frac{\textup{dS}}{\textup{dt}}$ = $\frac{\textup{220020}}{\textup{2S}}$

or

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

8 0

2 years ago