Zamir needs to determine the height of the building
1 answer:
Answer:
Height of the building = 115.4 ft.
Step-by-step explanation:
Height of building = AB + 46.4 + CD + 30.5
By applying Pythagoras theorem in ΔABP,
(26)² = (10)²+ (AB)²
676 - 100 = AB²
AB² = 576
AB = 24 ft
By applying sine rule in ΔCDE,
cos(60°) =
CD = CE ×
CD =
CD = 14.5 ft
Total Height = 24 + 46.4 + 14.5 + 30.5
= 115.4 ft
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Answer:
36
Step-by-step explanation:
We have to compute 4 distances and then add them up.
It may help to draw this first to see which distances to compute.
So I'm going to start with computing the distance from (0,0) to (5,12), then from (5,12) to (9,9), then from (9,9) to (12,5), and then finally from (12,5) to (0,0).
So distance from (0,0) to (5,12)
d=sqrt((5-0)^2+(12-0)^2)=sqrt(25+144)=sqrt(169)=13
Distance from (5,12) to (9,9)
d=sqrt((9-5)^2+(12-9)^2)=sqrt(4^2+3^2)=sqrt(16+9)=sqrt(25)=5
Distance from (9,9) to (12,5)
d=sqrt((12-9)^2+(9-5)^2)=sqrt(3^2+4^2)=sqrt(9+16)=sqrt(25)=5
Distance from (12,5) to (0,0)
d=sqrt((12-0)^2+(5-0)^2)=sqrt(12^2+5^2)=sqrt(144+25)=sqrt(169)=13.
Up all of our distances 13+5+5+13=(13+13)+(5+5)=26+10=36
