2 years ago

A line passes through the point (-10,5) and has a slope of -3/2. Write an equation in slope-intercept form for this line.

Mathematics

1 answer:

Mila [183]2 years ago

3 0

Answer:

$\large\boxed{y=-\dfrac{3}{2}x-10}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have the point (-10, 5) and the slope m = -3/2.

Substitute to the equation of a line:

$5=-\dfrac{3}{2}(-10)+b$

$5=(3)(5)+b$

$5=15+b$ <em>subtract 15 from both sides</em>

$5-15=15-15+b$

$-10=b\to b=-10$

Finally we have:

$\large{y=-\dfrac{3}{2}x-10}$

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