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Setler [38]
3 years ago
10

A line passes through the point (-10,5) and has a slope of -3/2. Write an equation in slope-intercept form for this line.

Mathematics
1 answer:
Mila [183]3 years ago
3 0

Answer:

\large\boxed{y=-\dfrac{3}{2}x-10}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have the point (-10, 5) and the slope m = -3/2.

Substitute to the equation of a line:

5=-\dfrac{3}{2}(-10)+b

5=(3)(5)+b

5=15+b          <em>subtract 15 from both sides</em>

5-15=15-15+b

-10=b\to b=-10

Finally we have:

\large{y=-\dfrac{3}{2}x-10}

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First, we must find the sequence    in explicit form. We can think of it as a line we are trying to get the slope-intercept form of. We have the points (1, 3) and (2, 8). Therefore, the slope is  8−32−1=51=5 . Now we just need the y-intercept. We can find it through substitution:

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Since that is negative, we will have to add instead.

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Therefore, the smallest integer    that makes sense and satisfies the inequality is 10.

So, the first 10 numbers must be added.

Honestly, it would have been quicker just to brute-force this.

Step-by-step explanation:

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