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Setler [38]
3 years ago
10

A line passes through the point (-10,5) and has a slope of -3/2. Write an equation in slope-intercept form for this line.

Mathematics
1 answer:
Mila [183]3 years ago
3 0

Answer:

\large\boxed{y=-\dfrac{3}{2}x-10}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have the point (-10, 5) and the slope m = -3/2.

Substitute to the equation of a line:

5=-\dfrac{3}{2}(-10)+b

5=(3)(5)+b

5=15+b          <em>subtract 15 from both sides</em>

5-15=15-15+b

-10=b\to b=-10

Finally we have:

\large{y=-\dfrac{3}{2}x-10}

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