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3 years ago

4,6,10,12,10,9,365,40,37,8 find mean median mode mid range

Mathematics

2 answers:

Lisa [10]3 years ago

7 0

4 , 6 , 8 , 9, 10, 10, 12, 37, 40, 365

We have 10 number

Median = (n+1)/2

Mp = (10 + 1)/2

Mp = 5,5

We have to calculate the median between the term 6 and 5

Median = (term6 + term5)/2

Median = (10+10)/2

Median = 10

Read more on Brainly.com - brainly.com/question/2737393#readmore

goldenfox [79]3 years ago

6 0

Leave the sequence organized

4 , 6 , 8 , 9, 10, 10, 12, 37, 40, 365

We have 10 number

Median = (n+1)/2

Mp = (10 + 1)/2

Mp = 5,5

We have to calculate the median between the term 6 and 5

Median = (term6 + term5)/2

Median = (10+10)/2

Median = 10

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4 0

2 years ago

Combine like terms. (Simplify your answer completely.) 2/5x+6+8/5x

Gemiola [76]

Answer:

16/5x

Step-by-step explanation:

as there is 2 5x so it will be 2 by 5x +6+ 8 by 5x

next there is two 5x and it will be 1 5x

then we will add 2+6+8=16

and there is already 5x ..simple.

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6 0

3 years ago

Please help no links please

allsm [11]

Answer:

Step-by-step explanation:

The secant- tangent angle MLK is half the difference of the intercepted arcs, that is

$\frac{1}{2}$ (KN - KM) = 70° ( multiply both sides by 2 to clear the fraction )

KN - KM = 140°

KN - 61° = 140° ( add 61° to both sides )

KN = 201° → C

8 0

3 years ago

f 20% of the population are homozygous for the scalp-wiggling allele •(qq, or q 2), then what proportion of the population is ho

11Alexandr11 [23.1K]

Answer:

The proportion of the population that is homozygous for the non-wiggling allele is 0.3056.

Step-by-step explanation:

Denote the variables as follows:

q² = number of people who are homozygous for the scalp-wiggling allele.

p² = number of people who are homozygous for the non-wiggling allele.

It is provided that the proportion of the population who are homozygous for the scalp-wiggling allele is, q² = 0.20.

Compute the value of q as follows:

$q^{2}=0.20\\q=\sqrt{0.20}\\=0.4472$

Compute the value of p as follows:

$p=1-q\\=1-0.4472\\=0.5528$

Compute the proportion of the population who are homozygous for the non-wiggling allele as follows:

$p^{2}=(0.5528)^{2}=0.30558784\approx0.3056$

Thus, the proportion of the population that is homozygous for the non-wiggling allele is 0.3056.

7 0

3 years ago