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goldfiish [28.3K]
3 years ago
13

Is (x-1) a factor of 2x3 - 15x2 + 22x + 15

Mathematics
1 answer:
Advocard [28]3 years ago
6 0

Answer:

Step-by-step explanation:

If x - 1 is a factor of the cubic, then 1 should result in 0 when you put it in the cubic for x. Does it?

f(1) = 2(1)^3 - 15(1)^2 + 22(1) + 15

f(1) = 2 - 15 + 22 + 15

f(1)= 24.

No the result is not zero. So x - 1 is not a factor.

However there must be something that makes this cubic go to zero. The easiest way to find it is to graph it.

The numbers that do make this zero are -0.5, 3, 5

Which mean that the factors are (2x+1)(x-3)(x - 5)

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An equilateral triangle has perimeter P. The length of one side is P/3. Which expression is equivalent to the length on one side
irina1246 [14]

Answer: 3\times \dfrac{P}{3}=P

Step-by-step explanation:

Given

The perimeter of one equilateral triangle is P

The lengths of the equilateral triangle are equal

Suppose x is the length of each side

\therefore 3\times x=P\\\\\Rightarrow x=\dfrac{P}{3}

i.e.

\Rightarrow 3\times \dfrac{P}{3}=P

3 0
3 years ago
Find the distance between the two points in simplest radical form.<br> (-9,8) and (-3, -1)
dmitriy555 [2]

Answer:

The distance between (-9, 8) and (-3, -1) will be:

\:d=3\sqrt{13} units

Step-by-step explanation:

Given the points

  • (-9, 8)
  • (-3, -1)

Finding the distance between (-9, 8) and (-3, -1)

d\:=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

   =\sqrt{\left(-3-\left(-9\right)\right)^2+\left(-1-8\right)^2}

   =\sqrt{\left(-3+9\right)^2+\left(-1-8\right)^2}

   =\sqrt{36+81}

   =\sqrt{117}

   =3\sqrt{13} units

Therefore, the distance between (-9, 8) and (-3, -1) will be:

\:d=3\sqrt{13} units

7 0
2 years ago
6
Sloan [31]

Triangle ABC is similar to triangle DEC, ∠B ≅ ∠E and 3DE = 2BC

<h3>What is transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>rotation, reflection, translation and dilation.</em>

Dilation is the increase or decrease in the size of a figure by a scale factor.

Right triangle ABC is reflected over AC, then dilated by a scale factor of 2/3 to form triangle DEC, hence:

Triangle ABC is similar to triangle DEC, corresponding angles are congruent (∠B ≅ ∠E) and DE = (2/3)BC i.e. 3DE = 2BC

Find out more on transformation at: brainly.com/question/4289712

#SPJ1

7 0
1 year ago
Let $f(x)$ be a function defined for all positive real numbers satisfying the conditions $f(x) &gt; 0$ for all $x &gt; 0$ and $f
algol [13]
Suppose we choose x=1 and y=\dfrac12. Then

f(x-y)=\sqrt{f(xy)+1}\implies f\left(\dfrac12\right)=\sqrt{f\left(\dfrac12\right)+1}\implies f\left(\dfrac12\right)=\dfrac{1+\sqrt5}2


Now suppose we choose x,y such that

\begin{cases}x-y=\dfrac12\\\\xy=2009\end{cases}


where we pick the solution for this system such that x>y>0. Then we find

\dfrac{1+\sqrt5}2=\sqrt{f(2009)+1}\implies f(2009)=\dfrac{1+\sqrt5}2

Note that you can always find a solution to the system above that satisfies x>y>0 as long as x>\dfrac12. What this means is that you can always find the value of f(x) as a (constant) function of f\left(\dfrac12\right).
3 0
3 years ago
Read 2 more answers
Is RATIONAL , IRRATIONAL,NON REAL NUMBERS <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B27" id="TexFormula1" title=" \sqrt{
Tanya [424]

Answer:

It's irrational

Step-by-step explanation:

the square root of 27 is equal to:

\sqrt{27} = \sqrt{3\cdot3\cdot3} = 3\sqrt{3}

We know that \sqrt{3} is an irrational number (but a real number), so 3\sqrt{3} is the same.

In case we need to prove that \sqrt{3} is irrational, please leave a comment.

8 0
3 years ago
Read 2 more answers
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