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kotegsom [21]
3 years ago
9

How do I divided factorials ?

Mathematics
1 answer:
Ugo [173]3 years ago
3 0

Answer:

Unfortunately factorials aren't the prettiest to divide but there are some tricks to help make it easier.

It's probably easiest to explain with an example.

Say we wanted to find the answer to \frac{6!}{4!}

Well we know that we can rewrite this as \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{4 \times 3 \times 2 \times 1}

So we can cancel out the 4 \times 3 \times 2 \times 1 from the numerator and denominator.

This leaves us with 6 \times 5 = 30 which is much easier than what we had before.

So I guess if you are dividing factorials, try to expand them and try to find parts that cancel out.

Hope this helps!

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Stabiliti daca marimile ale caror valori sunt trecute in tabelele urmatoare sunt direct proportionale.
kvv77 [185]

Vă rugăm să găsiți imaginea întrebării atașate mai jos:

Răspuns:

A este proporțională

B este proporțională

C nu este proporțional

D este proporțional

E nu este proporțională

F este proporțional

Explicație pas cu pas:

Pentru a determina proporționalitatea:

Obținem constanta proporționalității

Pentru valorile din tabelul 1;

Luând primul punct:

x = 1; y = 5

1 α 5

1 = 5k

k = 1/5

Test:

y = 15

x = k * y

x = 1/5 * 15; x = 3

Prin urmare; (a) este proporțională

B.)

x = 2; y = 6

2 α 6

2 = 6k

k = 2/6

k = 1/3

Test:

y = 15

x = k * y

x = 1/3 * 15; x = 5

Prin urmare; (b) este proporțională

C.)

x = 2; y = 6

7 α 3,5

7 = 3,5k

k = 7 / 3,5

k = 2

Test:

y = 5

x = 2 * 3.5

x = 7

Prin urmare; (c) nu este proporțională

x = 0,5; y = 1

0,5 α 1

0,5 = k

Test:

y = 4

x = k * y

x = 0,5 * 4; x = 2

Prin urmare; (d) este proporțională

x = 0,2; y = 2

0,2 α 2

0,2 = 2k

k = 0,2 / 2

k = 0,1

Test:

y = 4,5

x = 0,1 * 4,5

x = 0,45

Prin urmare; (e) nu este proporțională

x = 1; y = 12

1 α 12

1 = 12k

k = 1/12

Test:

y = 84

x = 1/12 * 84

x = 7

Prin urmare; (f) este proporțională

7 0
3 years ago
How many 4 digit palindromes contain both the digits 1 and 2
Norma-Jean [14]

What a clever sneaky little problem !

There can only be two of them:    1221  and  2112 .

8 0
3 years ago
Z to the power of 5 times z to the power of 6.<br><br> this equation is exponets.
zheka24 [161]

Answer:

z^11

Step-by-step explanation:

since both terms have "z" and the operation is multiplication, you <u>add</u><u> </u><u>the exponents</u><u> </u>together

6 0
3 years ago
Read 2 more answers
If f(x) = |x| and g(x) = |x| − 4, which transformation is applied to f(x) to get g(x)
velikii [3]
The graphs have precisely the same shape, but that of g(x) is that of f(x) translated 4 units DOWN.
7 0
3 years ago
What conjecture can you make about the sum of the first 22 positive even numbers?
alekssr [168]

Answer:

A.) The sum of the product of the number of terms and the number of terms plus one.

Step-by-step explanation:

So, we have the sum of the first 22 positive even numbers:

S = 2 + 4+ 6 + ... + 44

We know the sum of such sequence is given by the (sum of the first number (2) and the last number (44)) multiplied by the number of terms (11).

S = (2 + 44) * 11 = 46 * 11 = 506

Answer A tells us it should be the sum of the number of terms (22) by the number of terms plus one (22 + 1 = 23).

S = 22 * 23 = 506

That's confirmed.

Answer B would give 22 * 21 = 462, so it's not right

Answer C would give 22 * 2 = 44, obviously not right

Answer D would give 22 * 22 = 484, close but not right.

7 0
3 years ago
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