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drek231 [11]
2 years ago
11

Solve the question in the attached image.​

Mathematics
1 answer:
Greeley [361]2 years ago
3 0

9514 1404 393

Answer:

  1) 2/7√((x+3)^7) +C

  2) 2√(x+5) +C

Step-by-step explanation:

The power rule applies.

  ∫u^n du = u^(n+1)/(n+1)

1)

  \displaystyle\int{(x+3)^\frac{5}{2}}\,dx=\boxed{\dfrac{2}{7}(x+3)^\frac{7}{2}+C}

__

2)

  \displaystyle\int{(x+5)^{-\frac{1}{2}}}\,dx=\boxed{2(x+5)^\frac{1}{2}+C}

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1/2*(6*1+7)+11 show the result
fomenos
Well I got 17.5
You would start with                              6x1=6
Then you would add 7:                         6+7=13
Next you would multiply 13 by (1/2):    13(1/2)=6.5
Finally you would add 11 to 6.5:           6.5+11= 17.5
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