Answer:
December 31, Year 1 DR. Cr.
Accrued Interest Expense $7,500
Interest Payable $7,500
Explanation:
On December 31 Year 1 Interest was accrued and It was recorded by the Lighting Fixtures Inc. (LFI) but its outstanding now. Lighting Fixtures Inc. (LFI) paid the interest on January 15, at this time a payment entry of a payable interest was be made. Expense was charged on December 31 of year 1.
Answer:
the correct answer is
If a cost is a common cost of the segments on a segmented income statement, the costshould:A) be allocated to the segments on the basis of segment sales.
Explanation:
hope this helps u!!!
Answer:
Audit Risk and Materiality
These two concepts have an inverse relationship. When the materiality level is set low, the audit risk envisaged by the auditor is on the high side. When the materiality level is set high, the audit risk as perceived by the auditor is on the low side.
But, what exactly is materiality? Materiality refers to the basis that can change or influence the judgment of a reasonable person arising from a quantitative and qualitative omission or misstatement of a fact. And audit risk refers to the risk of material misstatement in the financial statements presented by a company.
Explanation:
The risk of material misstatement in the financial statements is the reason that professional auditors design their audit procedures to reduce the audit risk to an acceptably low level. This implies that auditors gather more audit evidence when the materiality is set to a low level, showing that audit risk has increased and vice versa.
Answer:
I believe the answer is B
Answer:
The manufacturer should announce a guaranteed mileage of 44528 miles
Explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What guaranteed mileage should the manufacturer announce
Only until the 5th percentile will have to be replaced, which is the value of X when Z has a pvalue of 0.05. So it is X when Z = -1.645.




The manufacturer should announce a guaranteed mileage of 44528 miles