Solve for u. 5u-15=30 simplify your answers as much as possible

Solve for b. 3(b + -2-8=-5 what is the answer?

ANEK [815]

Equation/Question:

Solve for b. 3(b + -2)-8=-5 what is the answer?

Answer/Steps to answer:

1.Simplify b+-2 to b−2.

3(b−2)−8=−5

2. Add 8 to both sides.

3(b-2)=-5+8

3. Simplify -5+8 to 3.

3(b-2)=3

4. Divide both sides by 3.

b-2=1

5. Add 2 to both sides.

b=1+2

6. Simplify 1+2 to 3.

b=3

Done by NeighborhoodDealer

8 0

3 years ago

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0

3 years ago

What is the solution to the inequality below? will give brainliest for correct answer

Mumz [18]

Answer: A

Step-by-step explanation:

7 0

3 years ago

Look at picture y=_ the height of the baseball after 5 seconds is ___ feet

Wittaler [7]

Answer:

y = -2(x -3)² +24
16 feet

Step-by-step explanation:

We expect the equation for y to be quadratic. Since the table is obviously symmetrical about x=3, we can start with the vertex form ...

y = a(x -3)² +b

Filling in the values from the first two table points, we get

For (x, y) = (0, 6):

6 = a(0 -3)² + b ⇒ 9a +b = 6

For (x, y) = (2, 22):

22 = a(2-3)² +b ⇒ a +b = 22

Subtracting the second equation from the first gives ...

(9a +b) -(a +b) = (6) -(22)

8a = -16 . . . . . . collect terms

a = -2 . . . . . . . . divide by 8

The second equation above tells us ...

b = 22 -a = 22 -(-2) = 24

So, our equation for y is ...

y = -2(x -3)² +24

__

The value of y for x=5 is ...

y = -2(5 -3)² +24 = 16

The height of the ball after 5 seconds is 16 feet.

5 0

3 years ago

Please help me with this!

GREYUIT [131]

Answer:

p=-7

Step-by-step explanation:

-11+10(p+10)=4-5(2p+11)

Firstly, expand the bracket

-11+10p+100=4-10p-55

Next, you collect like terms

10p+10p=4-55-100+11

20p=-140

Divide through by the coefficient of p

20p/20=-140/20

p=-7

5 0

2 years ago