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lawyer [7]
3 years ago
6

Factor completely. x^2−11x+24 Enter your answer in the box.

Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0
The problem factored is (x-8)(x-3)
Dafna1 [17]3 years ago
4 0

Answer:

The ecuation factored is (x-3)(x-8)

Step-by-step explanation:

  • First, consider that you can express any type of 2 grade polynomial  in terms of (x-x₁)(x-x₂)  where x₁ and x₂ are numbers or constants
  • In this example the polynomial x^{2}-11 x+24  is a 2 grade polynomial, you can notice that by the mayor exponent in x is 2 (x^2), so one technique to factor a 2 grade polynomial is using the cuadratic formula x = \frac {-b \pm \sqrt {b^2 - 4ac}}{2a} where a,b are the coefficients and c is the independent term of a x^2 + b x + c = 0

  • Having all the formulas and replacing a=1, b=11 and c=24:

x = \frac {- (11) \pm \sqrt {(- 11)^2 - 4 1 24}}{2 1}

This results in two values X₁=8 and X₂=3 ⇒ Replacing in (x-x₁)(x-x₂)

⇒  <u><em>Gives:</em></u><em>  </em>(x-8)(x-3)

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Answer:

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Step-by-step explanation:

We are given:

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and

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We have to find the value of f(2). In order to find f(2) we first have to find f(1)

f(n + 1) = - f(n) + 5

Using n = 0, we get:

f(0 + 1) = - f(0) + 5

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