Answer:
22 and 46
Step-by-step explanation:
let
one number is x
another is 2x+2
now 2x+2+x=68
or, 3x+2=68
3x=66
or x=66/3=22
so one number is 22 and another is (22X2+2)=46
Answer:
CI(99%) = ( 0.93 , 2.07)
Therefore at 99% confidence interval (a,b) = ( 0.93 , 2.07)
Critical value z(at 99% confidence) = z(0.005) = 2.58
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean gain x = 1.5
Standard deviation r = 0.58
Number of samples n = 7
Confidence interval = 99%
Critical value z(at 99% confidence) = z((1-0.99)/2)
z(0.005) = 2.58
Substituting the values we have;
1.5+/-2.58(0.58/√7)
1.5+/-2.58(0.2192)
1.5+/-0.565536
1.5+/-0.57
= ( 0.93 , 2.07)
Therefore at 99% confidence interval (a,b) = ( 0.93 , 2.07)
Puting it into the quadrait equation ((-b+-[b^2-4ac]^(1/2)/2a), we get that x= 31^(1/2)-5 or 31^(1/2)+5
f(x) + n - translate the graph of f(x) n units up
f(x) - n - translate the graph of f(x) n units down
f(x + n) - translate the graph of f(x) n units left
f(x - n) - translate the graph of f(x) n units right
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We have
y = |x - 2|
f(x) = |x| → f(x - 2) = |x - 2|
<h3>Answer: c. Translate the graph of y = |x| two units right.</h3>
