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jeyben [28]
3 years ago
9

if I walked 252 steps in total and 182 steps were in the shade, how many steps did I walk in the sun?

Mathematics
2 answers:
podryga [215]3 years ago
7 0
70

explanation: subtract 252-182=70
gregori [183]3 years ago
6 0
70 steps in the sun (:
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There are 100 tiles that were purchased to raise money for a new playground. The tiles will be laid along a walkway. Each tile i
faltersainse [42]

Answer:475 inches

Step-by-step explanation:

476 is the answer because:

100 * 4.75 = 475

*Therefore, the answer is 475 inches.

Hopefully this helps:)

7 0
2 years ago
Hypothesis Testing
Yuri [45]

Answer:

<u>Problem 1</u>: We conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

<u>Problem 2</u>: We conclude that the volume of Google stock has changed.

Step-by-step explanation:

<u>Problem 1:</u>

We are given that in a recent survey conducted by Pew Research, it was found that 156 of 295 adult Americans without a high school diploma were worried about having enough saved for retirement.

Let p = <em>proportion of adult Americans without a high school diploma who are worried about having enough saved for retirement</em>

So, Null Hypothesis, H_0 : p \leq 50%    {means that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement}

Alternate Hypothesis, H_A : p > 50%     {means that a majority of adult Americans without a high school diploma are worried about having enough saved for retirement}

This is a right-tailed test.

The test statistics that would be used here is <u>One-sample z-test</u> for proportions;

                       T.S.  =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of adult Americans who were worried about having enough saved for retirement = \frac{156}{295} = 0.53

           n = sample of adult Americans = 295

So, <u><em>the test statistics</em></u> =  \frac{0.53-0.50}{\sqrt{\frac{0.50(1-0.50)}{295} } }

                                    =  1.03

The value of z-test statistics is 1.03.

<u>Also, the P-value of the test statistics is given by;</u>

              P-value = P(Z > 1.03) = 1 - P(Z \leq 1.03)

                           = 1 - 0.8485 = <u>0.1515</u>

Now, at a 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is less than the critical value of z as 1.03 < 1.645, <u><em>so we insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

<u>Problem 2:</u>

We are given that a random sample of 35 trading days in 2014 resulted in a  sample mean of 3.28 million shares with a standard deviation of 1.68 million shares.

Let \mu = <em>mean daily volume in Google stock</em>

So, Null Hypothesis, H_0 : \mu = 5.44 million shares    {means that the volume of Google stock has not changed}

Alternate Hypothesis, H_A : \mu \neq 5.44 million shares     {means that the volume of Google stock has changed}

This is a two-tailed test.

The test statistics that would be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                       T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean volume in Google stock = 3.28 million shares

            s = sample standard deviation = 1.68 million shares

           n = sample of trading days = 35

So, <u><em>the test statistics</em></u> =  \frac{3.28-5.44}{\frac{1.68}{\sqrt{35} } }  ~ t_3_4

                                    =  -7.606

The value of t-test statistics is -7.606.

<u>Also, the P-value of the test statistics is given by;</u>

              P-value = P(t_3_4 < -7.606) = Less than 0.05%

Now, at a 0.05 level of significance, the t table gives a critical value of -2.032 and 2.032 at 34 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, <u><em>so we sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the volume of Google stock has changed.

8 0
2 years ago
A patient weighs 178 pounds in a nearest quarter pound. Find the minimum and maximum possible measurements.
Colt1911 [192]
177.75 lb; 178.25 lb
8 0
3 years ago
If the nth partial sum of the sequence an is given by
Art [367]

This is an example of a series in arithmetic progression.

The nth term an can be calculated using the formula:

an = a1 + (n – 1) d

<span>where: a1 = is the 1st term of the series</span>

d = common difference

<span>Calculating for the 1st term:</span>

a1 = 2k + 4 = 2 (1) + 4 = 6

Calculating for the common difference by :

d = a2 – a1

d = 2 (2) + 4 – 6

d = 2

 

Therefore calculating for an:

an = 6 + (n – 1) 2

an = 6 + 2n -2

an = 2n + 4

Therefore the answer is B. 2n+4

<span> </span>

6 0
3 years ago
Look at pic please and answer
madam [21]
22 students which is the answer
5 0
2 years ago
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