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sineoko [7]
2 years ago
14

What does ECONOMY MEAN PLZ TELL ME

Mathematics
2 answers:
ratelena [41]2 years ago
6 0
<span>The wealth and resources of a country or region, especially in terms of the production and consumption of goods and services.

OR

</span><span>Careful management of available resources.</span>
daser333 [38]2 years ago
6 0
 Careful, thrifty management of <span>resources</span>
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Match each system to the correct choice.
pogonyaev

Answer:

Option A - Neither. Lines intersect but are not perpendicular. One Solution.

Option B - Lines are equivalent. Infinitely many solutions

Option C - Lines are perpendicular. Only one solution

Option D - Lines are parallel. No solution

Step-by-step explanation:

The slope equation is known as;

y = mx + c

Where m is slope and c is intercept.

Now, two lines are parallel if their slopes are equal.

Looking at the options;

Option D with y = 12x + 6 and y = 12x - 7 have the same slope of 12.

Thus,the lines are parrallel, no solution.

Two lines are perpendicular if the product of their slopes is -1. Option C is the one that falls into this category because -2/5 × 5/2 = - 1. Thus, lines here are perpendicular and have one solution.

Two lines are said to intersect but not perpendicular if they have different slopes but their products are not -1.

Option A falls into this category because - 9 ≠ 3/2 and their product is not -1.

Two lines are said to be equivalent with infinitely many solutions when their slopes and y-intercept are equal.

Option B falls into this category.

8 0
2 years ago
Pls help meeeeeeeeeeeee
Assoli18 [71]

Answer:

3x/16+1/4

Step-by-step explanation:

5 0
2 years ago
Is a 90° angle perpendicular ​
Dima020 [189]

Answer:

yes

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
PLEASE HELP 25 POINTS
MrRissso [65]

The lcd would be 10x^3y^3

3 0
3 years ago
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1. There are 78 sophomores at a school. Each is required to take at least one year of either chemistry or physics, but they may
SVETLANKA909090 [29]

We are given that there are a total of 78 students. If we set the following variables:

\begin{gathered} C=\text{students only in chemestry} \\ P=\text{students only in physics} \\ PC=\text{students in physics and chemistry} \end{gathered}

Then, the sum of all of these must be 78, that is:

C+P+PC=78

Since there are 15 in chemistry and physics and 47 in chemistry, we may replace that into the equation and we get:

47+P+15=78

Simplifying:

62+P=78

Now we solve for P by subtracting 62 on both sides:

\begin{gathered} 62-62+P=78-62 \\ P=16 \end{gathered}

Therefore, there are 16 students in physics

3 0
1 year ago
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