Answer:
243
Step-by-step explanation:
Answer:
For a point defined bt a radius R, and an angle θ measured from the positive x-axis (like the one in the image)
The transformation to rectangular coordinates is written as:
x = R*cos(θ)
y = R*sin(θ)
Here we are in the unit circle, so we have a radius equal to 1, so R = 1.
Then the exact coordinates of the point are:
(cos(θ), sin(θ))
2) We want to mark a point Q in the unit circle sch that the tangent has a value of 0.
Remember that:
tan(x) = sin(x)/cos(x)
So if sin(x) = 0, then:
tan(x) = sin(x)/cos(x) = 0/cos(x) = 0
So tan(x) is 0 in the points such that the sine function is zero.
These values are:
sin(0°) = 0
sin(180°) = 0
Then the two possible points where the tangent is zero are the ones drawn in the image below.
Hey there!
43 + 7 = 50
so x = 7
Hope this helps
Have a great day (:
Answer:
Step-by-step explanation:
Call T the top
call G the bottom
T G B is a right triangle
37 at B, 90 at G, thus 53 at BTG
TGA is a right triangle
25 at A, 90 at G, thus 65 at ATG
thus 122 at ABT
law of sines:
sin 25 / BT = sin 12/ 57
so BT = 156 meters (first answer)
now angle ABT = 180 - 12 - 25
= 143
so
sin 143 /AT = sin12/57
AT = 164 meters, second answer
The answer would be 14x+5 I’m pretty sure