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Anna [14]
3 years ago
12

Dice how many rolls until you get 2 particular numbers

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
7 0
It takes 3 rolls to get what you want
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What is the missing reason in step 6? SSS congruency theorem CPCTC definition of a parallelogram opposite sides in a parallelogr
NARA [144]

For the two parallelogram to be congruent, their corresponding sides must be equal

<h3>Congruent figures</h3>

Two figures are said to be congruent if they are of the same shape and their corresponding sides and angles are congruent to each other. The SSS congruency theorem states that two figures are congruent of all their sides are congruent.

For the two parallelogram to be congruent, their corresponding sides must be equal

Find out more on similar figures at: brainly.com/question/26173060

7 0
2 years ago
A recipe uses 1 1/2 teaspoons of baking powder to make 8 blueberry muffins. How much baking powder is needed to make 36 muffins
sladkih [1.3K]
6.75 teaspoons 
So it takes 0.1875 teaspoon of baking powder to make one muffin. Then you just multiply 0.1875 by 36 and you get 6.75.   :)

3 0
3 years ago
Solve the inequality.<br> 5(w - 3) &lt; 5w + 20
saveliy_v [14]

Answer:

-15 < 20

Step-by-step explanation:

5(w - 3) < 5w + 20

Distribute;

5w - 15 < 5w + 20

Subtract 5w from both sides;

-15 < 20

7 0
2 years ago
Read 2 more answers
Consider the following two expressions, the only difference being the presence or absence of parentheses. expression 1:expressio
PilotLPTM [1.2K]

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

7 0
3 years ago
Write the quadratic function in standard form.<br> f(x) = -x2 + 2x + 4<br> f(x) =
goldenfox [79]

Answer:

f(x)=-1(x-2)^2+8

Step-by-step explanation:

Given:

The quadratic function is given as:

f(x)=-x^2+2x+4

The standard form of a quadratic function is given as:

f(x)=a(x-h)^2+k, where, 'a', 'h' and 'k' are real numbers.

Now, in order to convert the given function to standard form, we use completing by  square method.

-x^2+2x=-(x^2-2x)=-[(x-2)^2-2^2]=-[(x-2)^2-4]=-(x-2)^2+4

Now, f(x)=-x^2+2x+4 can be rewritten as:

f(x)=-(x-2)^2+4+4\\f(x)=-1(x-2)^2+8

Therefore, the standard form of the function is:

f(x)=-1(x-2)^2+8

7 0
3 years ago
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