3 years ago

Please help! Anwser photo below

Mathematics

2 answers:

Shkiper50 [21]3 years ago

3 0

Answer:

Step-by-step explanation:

skad [1K]3 years ago

3 0

B. Point C is the answer

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If sinX = 0.6, and X is in Quadrant II, then what is the value of cosX?

maxonik [38]

To calculate for cos X given that sin X=0.6 and is in Quadrant we proceed as follows:
sin X=0.6
Thus implies that:
x=arcsin 0.6
x=36.97
given that X is in the Quadrant ii then the value of x will be:
180-36.97
=143.13
hence cos X will be:
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the rectangle shown has a perimeter of 70cm and the given area. It’s length is 8 more than twice it’s width. Write and solve a s

vfiekz [6]

Dimensions of rectangle are:

Length = 26 cm

Width = 9 cm

Step-by-step explanation:

Perimeter of rectangle = 70 cm

Width= x

Length = 2x+8

We need to find the value of length and width of rectangle.

The formula used is:

$Periemter\,\,of\,\,rectangle=2(Length+Width)$

Putting values:

$Periemter\,\,of\,\,rectangle=2(Length+Width)\\70=2(2x+8+x)\\70=2(3x+8)\\70=6x+16\\70-16=6x\\54=6x\\x=54/6\\x=9$

So, Value of Width = x = 9 cm

Value of Length = 2x+8 = 2(9)+8 = 18+8=26 cm

So Dimensions of rectangle are:

Length = 26 cm

Width = 9 cm

Keywords: Perimeter of rectangle

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