To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
Intersecting arcs are created and connected.
Copy an angle by creating arcs with a compass
Answer:
Step-by-step explanation:
In general:
Volume = (the area of the base of the figure) times (the figure's height)
Here, the area of the base is 4 square feet, the height is 2 1/2 foot = 5/2 foot
Our Volume is then:
4 square feet * 5/2 foot = 10 cubic feet
Fill in each slot in the square with variables <em>a</em>, <em>b</em>, <em>c</em>, <em>d</em>, and <em>e</em>, in order from left-to-right, top-to-bottom. In a magic square, the sums across rows, columns, and diagonals all add up to the same number called the <em>magic sum</em>.
The magic sum is -3.9, since "diagonal 2" (bottom left to top right) has all the information we need:
3 + (-1.3) + (-5.6) = -3.9
Use this to find the remaining elements
<em>a</em> + <em>b</em> + (-5.6) = -3.9
<em>c</em> + (-1.3) + <em>d</em> = -3.9
3 + <em>e</em> + 0.02 = -3.9
<em>a</em> + <em>c</em> + 3 = -3.9
<em>b</em> + (-1.3) + <em>e</em> = -3.9
(-5.6) + <em>d</em> + 0.02 = -3.9
- diagonal 1 (top left to bottom right):
<em>a</em> + (-1.3) + 0.02 = -3.9
You will find
<em>a</em> = -2.62
<em>b</em> = 4.32
<em>c</em> = -4.28
<em>d</em> = 1.68
<em>e</em> = -6.92
