$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{y}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{y-5}{7-3}=\stackrel{\stackrel{slope}{\downarrow }}{-\cfrac{3}{2}}\implies \cfrac{y-5}{4}=-\cfrac{3}{2} \\\\\\ 2y-10=-3y\implies 5y-10=0\implies 5y=10\implies y=\cfrac{10}{5}\implies y=2$

7 0

2 years ago

What must be true to define the measure of a distance of an arc between the points A and B on a circle? A unit of measure must b

Leno4ka [110]

A.) A unit of measure must be defined for distance

6 0

3 years ago

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The first discount on a camera was 18%. The second discount was 20%. After the two discounts the price became $328. What was the

Lelechka [254]

Answer:

500

Step-by-step explanation:

Let x be the original price

Take the first discount

x - 18 percent

x - .18x = new price

x( 1-.18)

x ( .82) = new price

Now we take a 20 percent discount

This is on the discounted price, use .82x

.82x - 20 percent= 2nd discounted price

.82x - .20(.82x)

.82x -.164x

.656x= 2nd discounted price

.656x = 328

Divide each side by.656

.656x/.656 = 328/.656

x =500

The original price was 500

6 0

3 years ago

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